在我的应用程序中,我使用Spring Data和hibernate作为JPA提供程序来持久化和读取数据.
我有顶级实体类:
@Entity@Getter @Setter@table(name = "operation")@inheritance(strategy = inheritanceType.JOINED)@EqualsAndHashCode(of = {"operationID"})public abstract class Operation implements Serializable { public static final int OPERATION_ID_LENGTH = 20; @ID @Column(name = "operation_ID",length = OPERATION_ID_LENGTH,nullable = false,columnDeFinition = "char") private String operationID; @Column(name = "operation_type_code") @Getter(AccessLevel.NONE) @Setter(AccessLevel.NONE) private String operationTypeCode; @Temporal(TemporalType.TIMESTAMP) @Column(name = "begin_timestamp",nullable = false) private Date beginTimestamp = new Date(); @Temporal(TemporalType.TIMESTAMP) @Column(name = "end_timestamp") private Date endTimestamp; @Column(name = "operation_number",length = 6,columnDeFinition = "char") private String operationNumber; @Enumerated(EnumType.STRING) @Column(name = "operation_status",length = 32,nullable = false) private OperationStatus status; @ManyToOne(optional = false) @JoinColumn(name = "user_ID") private User user; @ManyToOne @JoinColumn(name = "terminal_ID") private Terminal terminal; @Column(name = "training_mode",nullable = false) private boolean trainingMode;}
对于继承的类,我有相应的存储库:
public interface ConcreteOperationRepository extends JpaRepository
我用以下方法进行集成测试:
@Transactional@Testpublic voID shouldFindOperationByPeriodAndStatusAnDWorkstationID() { Date from = new Date(Calendar.getInstance().getTime().getTime()); List
但是由于结果为空而我使用MysqL数据库时此测试失败(但是当我切换到HsqlDB时通过)
此外,如果我在测试开始时将延迟“Thread.sleep(1000)”延迟一秒,就在第一行之后,则此测试通过.
当我从Hibernate日志执行sql时,它给了我正确的结果.我的代码出了什么问题?
最佳答案在JPA中,日期需要时间提示.通常,您可以在设置JPA query参数时设置TemporalType:query.setParameter("from",from),TemporalType.TIMESTAMP);
使用Spring Data,您需要使用@Temporal
注释,因此您的查询将变为:
@query("SELECT o FROM ConcreteOperation o WHERE o.beginTimestamp BETWEEN :from AND :to AND o.status = :status AND o.terminal.deviceid = :deviceid AND o.trainingMode = :trainingMode")Collection
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