ios – 给定NSArray的JSON对象,如何在NSDictionary中为同一个键存储多个值?

ios – 给定NSArray的JSON对象,如何在NSDictionary中为同一个键存储多个值?,第1张

概述我知道除非将值存储在数组中,否则无法为同一个键设置多个值. 我有这个名为friMainDicArray的JSON对象的NSArray: { day = 0; "end_time" = "17:30"; "english_event" = "Lion Dance"; "english_performer" = "Legendary Gr 我知道除非将值存储在数组中,否则无法为同一个键设置多个值.

我有这个名为friMainDicArray的JSON对象的NSArray:

{        day = 0;        "end_time" = "17:30";        "english_event" = "lion Dance";        "english_performer" = "Legendary Group";        "image_link" = "schedule_miss_vn";        stage = 0;        "start_time" = "17:00";        "vIEt_event" = "<null>";        "vIEt_performer" = "Nh?m Legendary";    },{        day = 0;        "end_time" = "18:00";        "english_event" = Singing;        "english_performer" = "Ivan Cheong";        "image_link" = "schedule_miss_vn";        stage = 0;        "start_time" = "17:30";        "vIEt_event" = "Ca Nh?c";        "vIEt_performer" = "Ivan Cheong";    },{        day = 0;        "end_time" = "22:00";        "english_event" = Singing;        "english_performer" = "Between California and Summer";        "image_link" = "";        stage = 0;        "start_time" = "21:00";        "vIEt_event" = "Ca Nh?c";        "vIEt_performer" = "";    },{        day = 0;        "end_time" = "";        "english_event" = "End of Day";        "english_performer" = "";        "image_link" = "";        stage = 0;        "start_time" = "22:00";        "vIEt_event" = "";        "vIEt_performer" = "";    },{        day = 0;        "end_time" = "21:00";        "english_event" = Music;        "english_performer" = "DJ Happee From Channel 93.3";        "image_link" = "";        stage = 0;        "start_time" = "20:00";        "vIEt_event" = "";        "vIEt_performer" = "";    },{        day = 0;        "end_time" = "21:00";        "english_event" = Music;        "english_performer" = "Adam Cease";        "image_link" = "";        stage = 0;        "start_time" = "20:00";        "vIEt_event" = "";        "vIEt_performer" = "";    },{        day = 0;        "end_time" = "21:00";        "english_event" = "Ao Dai Fashion Show";        "english_performer" = "";        "image_link" = "";        stage = 0;        "start_time" = "20:00";        "vIEt_event" = "";        "vIEt_performer" = "";    }}

我给出了每个JsON对象,给定了start_time键值,但问题在于20:00键.我想将20:00作为键存储,并将JsON对象存储为值.问题是,最后3个JsON对象包含相同的20:00密钥,因此我想将这3个JsON对象存储为NSArray,并将其设置为20:00密钥.

我想实现这样的目标:

for (int i = 0; i < [friMainDicArray count]; i++){    [friMainDic setValue:friMainDicArray[i] forKey:[friMainDicArray[i] valueForKey:@"start_time" ] ]}

但是,我不确切地知道检查start_time键是否相同的逻辑,然后将其值添加到同一个键.

有人能以正确的方式指出我吗?

解决方法 我认为你可以循环数组,在setValueForKey之前,检查密钥是否已经存在,如果是,并且如果该密钥的值是NSDictionary类型,则将当前密钥与现有密钥组合为一个数组,否则值对于该键应该是NSArray,然后将当前项添加到该数组.

for (NSDictionary *item in friMainDicArray){    Nsstring *key = [item valueForKey:@"start_time"];    if ([friMainDic objectForKey:key]) {        ID value = [friMainDic objectForKey:key];        if ([value isKindOfClass:[NSArray class]]) {            NSMutableArray *array = [NSMutableArray arrayWithArray:(NSArray*)value];            [array addobject:item];            [friMainDic setValue:array forKey:key];        } else {            NSDictionary *dict = (NSDictionary*)value;            NSArray *array = @[dict,item];            [friMainDic setValue:array forKey:key];        }    } else {        [friMainDic setValue:item forKey:key];    }}
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