#include <sys/sysinfo.h>#include <stdio.h>int main() { int days,hours,mins; struct sysinfo sys_info; if(sysinfo(&sys_info) != 0) perror("sysinfo"); // Uptime days = sys_info.uptime / 86400; hours = (sys_info.uptime / 3600) - (days * 24); mins = (sys_info.uptime / 60) - (days * 1440) - (hours * 60); printf("Uptime: %ddays,%dhours,%dminutes,%ldseconds\n",days,mins,sys_info.uptime % 60); // Load Averages for 1,5 and 15 minutes printf("Load Avgs: 1min(%ld) 5min(%ld) 15min(%ld)\n",sys_info.loads[0],sys_info.loads[1],sys_info.loads[2]); printf("Total Ram: %lluk\tFree: %lluk\n",sys_info.totalram *(unsigned long long)sys_info.mem_unit / 1024,sys_info.freeram *(unsigned long long)sys_info.mem_unit/ 1024); // Number of processes currently running. printf("Number of processes: %d\n",sys_info.procs); return 0;}
我的问题是负载平均值不同于/ proc / loadavg
./a.out Uptime: 1days,4hours,1minutes,16secondsLoad Avgs: 1min(13248) 5min(14880) 15min(11840)Total Ram: 2052956k Free: 188104kNumber of processes: 265
为什么?我打印13248但“top”或“cat / proc / loadavg”给出0.24.问题是什么?
解决方法 该调用不会返回“错误”值.请注意,类型是整数,因此不能返回正常运行时打印的浮点数.有关如何解释返回值以及如何转换为更熟悉的浮点数的调查,请参阅this thread.
我的猜测(在阅读链接之前)是它的表现为按比例缩放65,535(216),这似乎也是他们发现的.因此除以65536.0,或者更清洁(如注释中所指出的)使用SI_LOAD_SHIFT常量并除以(浮点)(1<< SI_LOAD_SHIFT).
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