C程序 以下程序输出的结果为（ ）main(){ inta =5,b=-2,c=3;c=a%b; printf(“%dn”,c);}

A 1，VS2010亲测正确

后来看到有人这样解释

不管被除数和除数，只要有负号，那么求余的结果都是负的。 然后用他们绝对值求得的余数加上除数，就是最后的结果。 比如说 -7%5 先加上负号 ，然后7%5得2，现在变成-2了 再加上除数5 得到了3 ，同理....

#include "stdio.h"

int main(int argc,char *argv[]){

int a,b

double x,y

char ch1,ch2

printf("Please enter the data...\n")

scanf("%d%d%lf%lf %c%c",&a,&b,&x,&y,&ch1,&ch2)

printf("\na=%d,b=%d\nx=%f,y=%f\nch1=%c,ch2=%c\n",a,b,x,y,ch1,ch2)

return 0

}

运行样例：

Private Sub Form_Load()

Me.AutoRedraw = True

'姓名、年龄、通信地址、邮政编码、电话

Dim strname As String

Dim strage As String

Dim strAdd As String

Dim strYZ As String

Dim strPhone As String

strname = InputBox("请输入姓名：")

strage = InputBox("请输入年龄：")

strAdd = InputBox("请输入通信地址：")

strYZ = InputBox("请输入邮政编码：")

strPhone = InputBox("请输入电话：")

Print "姓名:" &strname

Print "年龄:" &strage

Print "通信地址:" &strAdd

Print "邮政编码:" &strYZ

Print "电话:" &strPhone

End Sub

第二题：

Private Sub Command1_Click()

Const dayS As Long = 86400

Const HourS As Long = 3600

Const minuteS As Long = 60

Dim i As String

i = InputBox("请输入秒数")

MsgBox "转换：" &Int(Val(i) / dayS) &"天" &Int((Val(i) - (Int(Val(i) / dayS)) * dayS) / HourS) &"时" &_

Int((Val(i) - (Int(Val(i) / dayS)) * dayS - Int((Val(i) - (Int(Val(i) / dayS)) * dayS) / HourS) * HourS) / minuteS) &"分" &Val(i) Mod 60 &"秒"

End Sub

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