2、import random #导入随机模块
3、
4、num = 1
5、yin_num = 0
6、shu_num = 0
7、while num2:
12、 print('不能出大于2的值')
13、 else:
14、 data = ['石头', '剪刀', '布']
15、 com = random.randint(0, 2)
16、 print(您出的是{},电脑出的是{}.format(data[user], data[com]))
17、 if user == com:
18、 print('平局')
19、 continue
20、 elif (user == 0 and com == 1) or (user == 1 and com == 2) or (user == 2 and com == 0):
21、 print('你赢了')
22、 yin_num += 1
23、 else:
24、 print('你输了')
25、 shu_num += 1
26、 num += 1
27、Python数字炸d小游戏代码:
28、import random
29、import time
30、
31、bomb = random.randint(1, 99)
32、print(bomb)
33、start = 0
34、end = 99
35、while 1 == 1:
36、
37、 people = int(input('请输入{}到{}之间的数:'.format(start, end)))
38、 if people >bomb:
39、 print('大了')
40、 end = people
41、 elif people <bomb:
42、 print('小了')
43、 start = people
44、 else:
45、 print('BOOM!!!')
46、 break
47、 print('等待电脑了输入{}到{}之间的数:'.format(start, end))
48、 time.sleep(1)
49、 com = random.randint(start + 1, end - 1)
50、 print('电脑输入:{}'.format(com))
51、 if com >bomb:
52、 print('大了')
53、 end = com
54、 elif com <bomb:
55、 print('小了')
56、 start = com
57、 else:
58、 print('BOOM!!!')
59、 break
pre{overflow-x: auto} 实现 消消乐的构成主要包括三部分:游戏主体、计分器、计时器,下面来看一下具体实现。
先来看一下游戏所需 Python 库。
import os import sys import time import pygame import random
定义一些常量,比如:窗口宽高、网格行列数等,代码如下:
WIDTH = 400 HEIGHT = 400 NUMGRID = 8 GRIDSIZE = 36 XMARGIN = (WIDTH - GRIDSIZE * NUMGRID) // 2 YMARGIN = (HEIGHT - GRIDSIZE * NUMGRID) // 2 ROOTDIR = os.getcwd() FPS = 30
接着创建一个主窗口,代码如下:
pygame.init() screen = pygame.display.set_mode((WIDTH, HEIGHT)) pygame.display.set_caption('消消乐')
看一下效果:
再接着在窗口中画一个 8 x 8 的网格,代码如下:
screen.fill((255, 255, 220)) # 游戏界面的网格绘制 def drawGrids(self): for x in range(NUMGRID):for y in range(NUMGRID): rect = pygame.Rect((XMARGIN+x*GRIDSIZE, YMARGIN+y*GRIDSIZE, GRIDSIZE, GRIDSIZE)) self.drawBlock(rect, color=(255, 165, 0), size=1 # 画矩形 block 框 def drawBlock(self, block, color=(255, 0, 0), size=2): pygame.draw.rect(self.screen, color, block, size)
看一下效果:
再接着在网格中随机放入各种拼图块,代码如下:
while True: self.all_gems = [] self.gems_group = pygame.sprite.Group() for x in range(NUMGRID):self.all_gems.append([])for y in range(NUMGRID): gem = Puzzle(img_path=random.choice(self.gem_imgs), size=(GRIDSIZE, GRIDSIZE), position=[XMARGIN+x*GRIDSIZE, YMARGIN+y*GRIDSIZE-NUMGRID*GRIDSIZE], downlen=NUMGRID*GRIDSIZE) self.all_gems[x].append(gem) self.gems_group.add(gem) if self.isMatch()[0] == 0:break
看一下效果:
再接着加入计分器和计时器,代码如下:
# 显示得分 def drawScore(self): score_render = self.font.render('分数:'+str(self.score), 1, (85, 65, 0)) rect = score_render.get_rect() rect.left, rect.top = (55, 15) self.screen.blit(score_render, rect) # 显示加分 def drawAddScore(self, add_score): score_render = self.font.render('+'+str(add_score), 1, (255, 100, 100)) rect = score_render.get_rect() rect.left, rect.top = (250, 250) self.screen.blit(score_render, rect) # 显示剩余时间 def showRemainingTime(self): remaining_time_render = self.font.render('倒计时: %ss' % str(self.remaining_time), 1, (85, 65, 0)) rect = remaining_time_render.get_rect() rect.left, rect.top = (WIDTH-190, 15) self.screen.blit(remaining_time_render, rect)
看一下效果:
当设置的游戏时间用尽时,我们可以生成一些提示信息,代码如下:
while True: for event in pygame.event.get():if event.type == pygame.QUIT: pygame.quit() sys.exit()if event.type == pygame.KEYUP and event.key == pygame.K_r: flag = True if flag:break screen.fill((255, 255, 220)) text0 = '最终得分: %s' % score text1 = '按 R 键重新开始' y = 140 for idx, text in enumerate([text0, text1]):text_render = font.render(text, 1, (85, 65, 0))rect = text_render.get_rect()if idx == 0: rect.left, rect.top = (100, y)elif idx == 1: rect.left, rect.top = (100, y)y += 60screen.blit(text_render, rect) pygame.display.update()
看一下效果:
说完了游戏图形化界面相关的部分,我们再看一下游戏的主要处理逻辑。
我们通过鼠标来 *** 纵拼图块,因此程序需要检查有无拼图块被选中,代码实现如下:
def checkSelected(self, position): for x in range(NUMGRID):for y in range(NUMGRID): if self.getGemByPos(x, y).rect.collidepoint(*position): return [x, y] return None
我们需要将鼠标连续选择的拼图块进行位置交换,代码实现如下:
def swapGem(self, gem1_pos, gem2_pos): margin = gem1_pos[0] - gem2_pos[0] + gem1_pos[1] - gem2_pos[1] if abs(margin) != 1:return False gem1 = self.getGemByPos(*gem1_pos) gem2 = self.getGemByPos(*gem2_pos) if gem1_pos[0] - gem2_pos[0] == 1:gem1.direction = 'left'gem2.direction = 'right' elif gem1_pos[0] - gem2_pos[0] == -1:gem2.direction = 'left'gem1.direction = 'right' elif gem1_pos[1] - gem2_pos[1] == 1:gem1.direction = 'up'gem2.direction = 'down' elif gem1_pos[1] - gem2_pos[1] == -1:gem2.direction = 'up'gem1.direction = 'down' gem1.target_x = gem2.rect.left gem1.target_y = gem2.rect.top gem1.fixed = False gem2.target_x = gem1.rect.left gem2.target_y = gem1.rect.top gem2.fixed = False self.all_gems[gem2_pos[0]][gem2_pos[1]] = gem1 self.all_gems[gem1_pos[0]][gem1_pos[1]] = gem2 return True
每一次交换拼图块时,我们需要判断是否有连续一样的三个及以上拼图块,代码实现如下:
def isMatch(self): for x in range(NUMGRID):for y in range(NUMGRID): if x + 2 -2: for each in [res_match[1], res_match[1]+1, res_match[1]+2]: gem = self.getGemByPos(*[each, start]) if start == res_match[2]: self.gems_group.remove(gem) self.all_gems[each][start] = None elif start >= 0: gem.target_y += GRIDSIZE gem.fixed = False gem.direction = 'down' self.all_gems[each][start+1] = gem else: gem = Puzzle(img_path=random.choice(self.gem_imgs), size=(GRIDSIZE, GRIDSIZE), position=[XMARGIN+each*GRIDSIZE, YMARGIN-GRIDSIZE], downlen=GRIDSIZE) self.gems_group.add(gem) self.all_gems[each][start+1] = gem start -= 1 elif res_match[0] == 2:start = res_match[2]while start > -4: if start == res_match[2]: for each in range(0, 3): gem = self.getGemByPos(*[res_match[1], start+each]) self.gems_group.remove(gem) self.all_gems[res_match[1]][start+each] = None elif start >= 0: gem = self.getGemByPos(*[res_match[1], start]) gem.target_y += GRIDSIZE * 3 gem.fixed = False gem.direction = 'down' self.all_gems[res_match[1]][start+3] = gem else: gem = Puzzle(img_path=random.choice(self.gem_imgs), size=(GRIDSIZE, GRIDSIZE), position=[XMARGIN+res_match[1]*GRIDSIZE, YMARGIN+start*GRIDSIZE], downlen=GRIDSIZE*3) self.gems_group.add(gem) self.all_gems[res_match[1]][start+3] = gem start -= 1
之后反复执行这个过程,直至耗尽游戏时间,游戏结束。
最后,我们动态看一下游戏效果。
总结
本文我们使用 Python 实现了一个简单的消消乐游戏,有兴趣的可以对游戏做进一步扩展,比如增加关卡等。
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