较复杂的c语言程序设计源代码

较复杂的c语言程序设计源代码,第1张

一个“歼灭敌机”的小游戏,DEVc++通过编译:

#include <stdio.h>

#include <conio.h>

#include <stdlib.h>

#include <windows.h>

#include <time.h>

#define zlx 10  //增量坐标(x)让游戏框不靠边

#define zly 3   //增量坐标(y)让誉清游戏框不靠边

#define W 26  //游戏框的宽度

#define H 24  //游戏框的高度

int jiem[22][22]={0}, wj=10  //界面数组, 我机位置(初值为10)

int speed=4,density=30, score=0,death=0//敌机速度, 敌机密度, 玩家成绩,死亡次数

int m=0,n=0 // m,n是控制敌机的变量

void gtxy (int x, int y)  //控制光标位置的函数

{ COORD pos

pos.X = x  pos.Y = y

SetConsoleCursorPosition ( GetStdHandle (STD_OUTPUT_HANDLE), pos )

}

void Color(int a)  //设定颜色的函数(a应为1-15)

{ SetConsoleTextAttribute( GetStdHandle(STD_OUTPUT_HANDLE), a )}

void yinc(int x=1,int y=0)   //隐藏光标的函数

{ CONSOLE_CURSOR_INFO  gb={x,y}   //y设为0即隐藏

SetConsoleCursorInfo(GetStdHandle(STD_OUTPUT_HANDLE), &gb)

}

void csh( )  //初始化函数

{ int i

Color(7)

gtxy(zlx,zly)printf("╔")  gtxy(zlx+W-2,zly)printf("╗")  //左上角和右上角的框角

gtxy(zlx,zly+H-1)printf("╚")gtxy(zlx+W-2,zly+H-1)printf("╝")//下边两框角

for(i=2i<W-2i+=2) {gtxy(zlx+i,zly)  printf("═樱虚搭")}      //打印上横框

for(i=2i<W-2i+=2) {gtxy(zlx+i,zly+H-1)printf("═")}  //打印下横框

for(i=1i<H-1i++) { gtxy(zlx,zly+i) printf("║")}       //打印左竖框

for(i=1i<H-1i++) {gtxy(zlx+W-2,zly+i)printf("║")}  //打印右竖框

Color(14)gtxy(19,2)printf("歼灭敌机")Color(10)

gtxy(37,5)printf("设置:Esc ")

gtxy(37,7)printf("发射:↑ ")

gtxy(37,9)printf("控制:← → ")

gtxy(37,11)printf("得分:%d"脊拿,score)

gtxy(37,13)printf("死亡:%d",death)

yinc(1,0)

}

void qcjm( )  //清除界面函数

{int i,j

for(i=0i<H-2i++)

for(j=0j<W-4j++){gtxy(zlx+2+j,zly+1+i)printf(" ")}

}

void feiji( )  //飞机移动函数

{int i,j

for(i=21i>=0i--)  //从底行往上是为了避免敌机直接冲出数组

  for(j=0j<22j++)

     {if(i==21&&jiem[i][j]==3) jiem[i][j]=0  //底行赋值0 以免越界

       if(jiem[i][j]==3) jiem[i][j]=0, jiem[i+1][j]=3

     }

if(jiem[20][wj]==3&&jiem[21][wj]==1) death++

}

void zidan( )  //子d移动函数

{ int i,j

for(i=0i<22i++)

  for(j=0j<22j++)

     {if(i==0&&jiem[i][j]==2) jiem[i][j]=0

     if(jiem[i][j]==2) { if(jiem[i-1][j]==3) score+=100,printf("\7")

                                  jiem[i][j]=0,jiem[i-1][j]=2}

     }

}

void print(  )  //输出界面函数

{int i,j

qcjm( )

for(i=0i<22i++)

for(j=0j<22j++)

{ gtxy(12+j,4+i)

if(jiem[i][j]==3) {Color(13)printf("□")}

if(jiem[i][j]==2) {Color(10)printf(".")}

if(jiem[i][j]==1) {Color(10)printf("■")}

}

gtxy(37,11)Color(10)printf("得分:%d",score)

gtxy(37,13)printf("死亡:%d",death)

}

void setting( )  //游戏设置函数

{ qcjm( )

gtxy(12,4)printf("选择敌机速度:")

gtxy(12,5)printf("  1.快 2.中 3.慢>>")

switch(getche( ))

    {case '1': speed=2break

     case '2': speed=4break

     case '3': speed=5break

     default: gtxy(12,6)printf("  错误!默认值")

   }

gtxy(12,7)printf("选择敌机密度:")

gtxy(12,8)printf("  1.大 2.中 3.小>>")

switch(getche( ))

     {case '1': density=20break

      case '2': density=30 break

      case '3': density=40break

       default: gtxy(12,9)printf("  错误!默认值")

     }

for(int i=0i<22i++)

 for(int j=0j<22j++) jiem[i][j]=0

jiem[21][wj=10]=1jiem[0][5]=3

gtxy(12,10)printf("  按任意键保存...")

getch( )

qcjm( )

}

void run( )  //游戏运行函数

{ jiem[21][wj]=1  //值为1代表我机(2则为子d)

jiem[0][5]=3   //值为3代表敌机

SetConsoleTitle("歼灭敌机") //设置窗口标题

while(1)

  { if (kbhit( ))  //如有键按下,控制我机左右移动、发射或进行设定

       {int key

        if((key=getch( ))==224) key=getch( )

        switch(key)

           {case 75: if(wj>0) jiem[21][wj]=0,jiem[21][--wj]=1break

            case 77: if(wj<20) jiem[21][wj]=0,jiem[21][++wj]=1 break

            case 72: jiem[20][wj]=2break

           case 27: setting( )

         }

      }

   if(++n%density==0)  //控制产生敌机的速度

      { n=0srand((unsigned)time(NULL))

        jiem[0][rand( )%20+1]=3

      }

   if(++m%speed==0) { feiji( )m=0}  //控制敌机移动速度(相对子d而言)

   zidan( )  //子d移动

   print( )  //输出界面

Sleep(120)  //延时120毫秒

  }

}

int main( )

{csh( )

 run( )

 return 0

}

int main()

{

int a=3,b=2,c=2.5

float y=0

y=(float)(a+b)/锋芹团3+(int)c

printf("首判%f"银橘,y)

return 0

}

下面是我初学时的一个列子,是计算时间的。。

可以进行时间相加减```

由于我是在linux下吵宴运行的,再转到window上所以格式会有点乱```谅解!!!

代码也没有进行优化颤碰团处理的```

#include <stdio.h>

#include <stdlib.h>

typedef struct time

{

int year

int month

int day

int hour

int minute

int sec

} ST_TIME

ST_TIME date

void add_sec(int secs)

void add_minute(int minutes)

void add_hour(int hours)

void add_day(int days)

int maxday(int leap, int month)

void add_month(int months)

void add_year(int years)

void sub_sec(int secs)

void sub_minute(int minutes)

void sub_hour(int hours)

void sub_day(int days)

void sub_month(int months)

void sub_year(int years)

void sum(void)

void sub(void)

void init_system(void)

int add_number

int main(int argc, char *argv[])

{

char array[20]

char emblem

init_system()

printf("Press the '+' or '-' to control.\n")

scanf("%c",&emblem)

switch (emblem)

{

case '+':

{

sum()

break

}

case '-':

{

sub()

break

}

}

sprintf(array,"%d-%02d-%02d %02d:%02d:%02d",date.year,date.month,

date.day,date.hour,date.minute,date.sec)

printf("%s\n",array)

return 0

}

void init_system(void)

{

char str[20]

char *p

p = str

printf("Enter the date:\n")

printf("Be sure your inputs like that:2008 12 12 12 12 12\n")

gets(str)

date.year = atoi(p)

date.month = atoi(p+5)

date.day = atoi(p+8)

date.hour = atoi(p+11)

date.minute = atoi(p+14)

date.sec = atoi(p+17)

}

void sum(void)

{

int lab

printf("please choose the option:\n")

printf("1: add the secs\茄橘n")

printf("2: add the minutes\n")

printf("3: add the hours\n")

printf("4: add the days\n")

printf("5: add the months\n")

printf("6: add the years\n")

while (getchar() != '\n')

scanf("%d",&lab)

switch (lab)

{

case 1 :

{

printf("enter the increased secs:")

scanf("%d",&add_number)

add_sec(add_number)

break

}

case 2:

{

printf("enter the increased minutes:")

scanf("%d",&add_number)

add_minute(add_number)

break

}

case 3:

{

printf("enter the increased hours:")

scanf("%d",&add_number)

add_hour(add_number)

break

}

case 4:

{

printf("enter the increased days:")

scanf("%d",&add_number)

add_day(add_number)

break

}

case 5:

{

printf("enter the increased months:")

scanf("%d",&add_number)

add_month(add_number)

break

}

case 6:

{

printf("enter the increased years:")

scanf("%d",&add_number)

add_year(add_number)

break

}

}

}

void sub(void)

{

int lab

printf("please choose the option:\n")

printf("1: reduce the secs\n")

printf("2: reduce the minutes\n")

printf("3: reduce the hours\n")

printf("4: reduce the days\n")

printf("5: reduce the months\n")

printf("6: reduce the years\n")

scanf("%d",&lab)

switch (lab)

{

case 1 :

{

printf("enter the reduced secs:")

scanf("%d",&add_number)

sub_sec(add_number)

break

}

case 2:

{

printf("enter the reduced minutes:")

scanf("%d",&add_number)

sub_minute(add_number)

break

}

case 3:

{

printf("enter the reduced hours:")

scanf("%d",&add_number)

sub_hour(add_number)

break

}

case 4:

{

printf("enter the reduced days:")

scanf("%d",&add_number)

sub_day(add_number)

break

}

case 5:

{

printf("enter the reduced months:")

scanf("%d",&add_number)

sub_month(add_number)

break

}

case 6:

{

printf("enter the increased years:")

scanf("%d",&add_number)

sub_year(add_number)

break

}

}

}

void add_sec(int secs)

{

date.sec = date.sec + secs

while (date.sec >= 60)

{

add_minute(1)

date.sec = date.sec - 60

}

}

void add_minute(int minutes)

{

date.minute = date.minute + minutes

while (date.minute >= 60)

{

add_hour(1)

date.minute = date.minute - 60

}

}

void add_hour(int hours)

{

date.hour = date.hour + hours

while (date.hour >= 24)

{

add_day(1)

date.hour = date.hour - 24

}

}

void add_day(int days)

{

int leap

date.day = days + date.day

/****************************************

* 功能:判断是否为闰年 *

****************************************/

if ((date.year%4 == 0 &&date.year%100 != 0) || (date.year%400 == 0))

{

leap = 1/*是闰年则leap的值为1*/

}

else

{

leap = 0/*不是则leap的值为0 */

}

while (date.day >maxday(leap,date.month))

{

if ((date.year%4 == 0 &&date.year%100 != 0) || (date.year%400 == 0))

{

leap = 1/*是闰年则leap的值为1*/

}

else

{

leap = 0/*不是则leap的值为0 */

}

date.day = date.day - maxday(leap,date.month)

add_month(1)

}

}

void add_month(int months)

{

int leap

date.month = date.month + months

while (date.month >12)

{

date.month = date.month - 12

add_year(1)

}

if ((date.year%4 == 0 &&date.year%100 != 0) || (date.year%400 == 0))

{

leap = 1/*是闰年则leap的值为1*/

}

else

{

leap = 0/*不是则leap的值为0 */

}

if (leap==1 &&date.month==2 &&date.day>=29)

{

date.day = 29

}

else if (leap==0 &&date.month==2 &&date.day>=28)

{

date.day = 28

}

}

void add_year(int years)

{

int leap

date.year = date.year + years

if ((date.year%4 == 0 &&date.year%100 != 0) || (date.year%400 == 0))

{

leap = 1/*是闰年则leap的值为1*/

}

else

{

leap = 0/*不是则leap的值为0 */

}

if (leap==1 &&date.month==2 &&date.day>=29)

{

date.month = 2

date.day = 29

}

else if (leap==0 &&date.month==2 &&date.day>=28)

{

date.month = 2

date.day = 28

}

}

void sub_sec(int secs)

{

date.sec = date.sec - secs

while (0 >date.sec)

{

sub_minute(1)

date.sec = date.sec + 60

}

}

void sub_minute(int minutes)

{

date.minute = date.minute - minutes

while (0 >date.minute)

{

sub_hour(1)

date.minute = date.minute + 60

}

}

void sub_hour(int hours)

{

date.hour = date.hour - hours

while (0 >date.hour)

{

sub_day(1)

date.hour = date.hour + 24

}

}

void sub_day(int days)

{

int leap

date.day = date.day - days

/****************************************

* 功能:判断是否为闰年 *

****************************************/

if ((date.year%4 == 0 &&date.year%100 != 0) || (date.year%400 == 0))

{

leap = 1/*是闰年则leap的值为1*/

}

else

{

leap = 0/*不是则leap的值为0 */

}

while (0 >= date.day)

{

if ((date.year%4 == 0 &&date.year%100 != 0) || (date.year%400 == 0))

{

leap = 1/*是闰年则leap的值为1*/

}

else

{

leap = 0/*不是则leap的值为0 */

}

date.day = date.day + maxday(leap,date.month-1)

sub_month(1)

}

}

void sub_month(int months)

{

int leap

date.month = date.month - months

while (0 >= date.month)

{

date.month = date.month + 12

sub_year(1)

}

if ((date.year%4 == 0 &&date.year%100 != 0) || (date.year%400 == 0))

{

leap = 1/*是闰年则leap的值为1*/

}

else

{

leap = 0/*不是则leap的值为0 */

}

if (leap==1 &&date.month==2 &&date.day>=29)

{

date.day = 29

}

else if (leap==0 &&date.month==2 &&date.day>=28)

{

date.day = 28

}

}

void sub_year(int years)

{

int leap

date.year = date.year - years

if ((date.year%4 == 0 &&date.year%100 != 0) || (date.year%400 == 0))

{

leap = 1/*是闰年则leap的值为1*/

}

else

{

leap = 0/*不是则leap的值为0 */

}

if (leap==1 &&date.month==2 &&date.day>=29)

{

date.month = 2

date.day = 29

}

else if (leap==0 &&date.month==2 &&date.day>=28)

{

date.month = 2

date.day = 28

}

}

int maxday(int leap, int month)

{

int max_day/*用于返回此月份的最大值*/

switch (month)

{

case 4:

{

max_day = 30

break

}

case 6:

{

max_day = 30

break

}

case 9:

{

max_day = 30

break

}

case 11:

{

max_day = 30

break

}

case 2:

{

if (leap == 1)

{

max_day = 29

break

}

else

{

max_day = 28

break

}

}

default: max_day = 31

}

return max_day

我这里还有很多的,如果要的话,就联系我121779988````

只不过我也是个菜鸟级的``


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原文地址: http://outofmemory.cn/yw/12454619.html

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