关闭:首先调用
ExcelFile,然后调用该
.parse方法并将表单名称传递给该方法。
>>> xl = pd.ExcelFile("dummydata.xlsx")>>> xl.sheet_names[u'Sheet1', u'Sheet2', u'Sheet3']>>> df = xl.parse("Sheet1")>>> df.head() Tid dummy1 dummy2 dummy3 dummy4 dummy5 2006-09-01 00:00:00 0 5.894611 0.605211 3.842871 8.265307 1 2006-09-01 01:00:00 0 5.712107 0.605211 3.416617 8.301360 2 2006-09-01 02:00:00 0 5.105300 0.605211 3.090865 8.335395 3 2006-09-01 03:00:00 0 4.098209 0.605211 3.198452 8.170187 4 2006-09-01 04:00:00 0 3.338196 0.605211 2.970015 7.765058 dummy6 dummy7 dummy8 dummy9 0 0.623354 0 2.579108 2.681728 1 0.554211 0 7.210000 3.028614 2 0.567841 0 6.940000 3.644147 3 0.581470 0 6.630000 4.016155 4 0.595100 0 6.350000 3.974442
您正在做的是调用驻留在类本身而不是实例上的方法,这是可以的(尽管不是很惯用),但是如果这样做,则还需要传递工作表名称:
>>> parsed = pd.io.parsers.ExcelFile.parse(xl, "Sheet1")>>> parsed.columnsIndex([u'Tid', u'dummy1', u'dummy2', u'dummy3', u'dummy4', u'dummy5', u'dummy6', u'dummy7', u'dummy8', u'dummy9'], dtype=object)
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