c#中一个字符串数组如何添加到listview中

（一）我们先建立一个二维数组

listView1.View

=

View.Details

listView1.Columns.Add("姓名")

listView1.Columns.Add("语文")

listView1.Columns.Add("数学")

listView1.Columns.Add("科学")

listView1.Columns.Add("英语")

string[,]

chengji

=

new

string[4,

5]

chengji[0,

0]

=

"小王"

chengji[0,

1]

=

"90"

chengji[0,

2]

=

"98"

chengji[0,

3]

=

"88"

chengji[0,

4]

=

"92"

chengji[1,

0]

=

"小李"

chengji[1,

1]

=

"92"

chengji[1,

2]

=

"94"

chengji[1,

3]

=

"98"

chengji[1,

4]

=

"93"

chengji[2,

0]

=

"小黄"

chengji[2,

1]

=

"91"

chengji[2,

2]

=

"92"

chengji[2,

3]

=

"93"

chengji[2,

4]

=

"94"

chengji[3,

0]

=

"小张"

chengji[3,

1]

=

"95"

chengji[3,

2]

=

"94"

chengji[3,

3]

=

"93"

chengji[3,

4]

=

"92"

（二）下面是几种分列显示二维数组的几种方法。

1、第一种分列显示方法：

listView1.Clear()

for

(int

i

=

0

i

<

chengji.GetLength(0)

i++)

{

ListViewItem

bb

=

new

ListViewItem(new

string[]

{

chengji[i,

0],

chengji[i,

1],

chengji[i,

2],

chengji[i,

3],

chengji[i,

4]

})

listView1.Items.Add(bb)

}

2、第二种分列显示方法：

上面的listview分列显示还可以用下面的方法。

listView1.Clear()

ListViewItem

cj

for

(int

i

=

0

i

<

chengji.GetLength(0)

i++)

{

cj

=

new

ListViewItem(chengji[i,0])

cj.SubItems.Add(chengji[i,

1])

cj.SubItems.Add(chengji[i,2])

cj.SubItems.Add(chengji[i,

3])

cj.SubItems.Add(chengji[i,

4])

listView1.Items.Add(cj)

3、第三种分列显示方法：

如果我们把二维数组转化为一维数组（即结合上面两种方法）还可以用下面的方法分列显示。

listView1.Clear()

ListViewItem

cjj

string[]

sstr

=

new

string[chengji.GetLength(1)]

for

(int

i

=

0

i

<

chengji.GetLength(0)

i++)

{

for

(int

j

=

0

j

<

chengji.GetLength(1)

j++)

{

sstr[j]

=

chengji[i,

j]

}

cjj

=

new

ListViewItem(sstr)

listView1.Items.Add(cjj)

}

绑定的时候：

foreach (var item in ac)

{

                ListViewItem ii = new ListViewItem(item.gonghao)

                ii.SubItems.Add(item.name)

                ii.SubItems.Add(item.Sex)

                ii.SubItems.Add(item.age)

                ii.SubItems.Add(item.pingjia)

                ii.SubItems.Add(item.defen)

                this.listView1.Items.Add(ii)

}

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