django forms怎么获取登录用户

Django获取登陆用户的手段就是request.user。

如果你想传给form字段，可以先做一个model的object实例，把request.user传给这个object实例的相关字段，然后把这个实例传给forms实例即可。

首先我们要新建一个用户名，用来登陆管理网站，可以使用如下命令：\x0d\x0apython manage.py createsuperuser\x0d\x0a输入想要使用的用户名：\x0d\x0a\x0d\x0aUsername (leave blank to use 'administrator'): user01\x0d\x0a输入email：\x0d\x0a\x0d\x0aEmail address: (在这里输入你的自己的邮箱帐号)\x0d\x0a输入密码，需要输入两次，并且输入密码时不会显示出来：\x0d\x0a\x0d\x0aPassword:\x0d\x0aPassword (again):\x0d\x0a当两次密码都相同的时候，就会提示超级帐号创建成功。\x0d\x0aSuperuser created successfully.\x0d\x0a\x0d\x0a运行服务：\x0d\x0a\x0d\x0apython manage.py runserver

settings.py

MIDDLEWARE_CLASSES = (

'django.middleware.common.CommonMiddleware',

'django.contrib.sessions.middleware.SessionMiddleware',

'django.middleware.csrf.CsrfViewMiddleware',

'django.contrib.auth.middleware.AuthenticationMiddleware',

'django.contrib.messages.middleware.MessageMiddleware',

)

INSTALLED_APPS = (

'django.contrib.auth',

'django.contrib.contenttypes',

'django.contrib.sessions',

'django.contrib.sites',

'django.contrib.messages',

'django.contrib.admin',

'django.contrib.staticfiles',

)

urls.py

from django.conf.urls.defaults import *

from django.contrib import admin

from django.conf import settings

admin.autodiscover()

urlpatterns = patterns('',

url(r'^admin/', include(admin.site.urls)),

)

if settings.DEBUG:

urlpatterns = patterns('',

url(r'^media/(?P<path>.*)$', 'django.views.static.serve',

{'document_root': settings.MEDIA_ROOT, 'show_indexes': True}),

url(r'', include('django.contrib.staticfiles.urls')),

) + urlpatterns

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