C语言将字符串每个字符后面加上一个字符串？

C语言代码和运行结果如下：

输出符合样例，望采纳~

附源码：

#include <stdio.h>

#include <string.h>

void join(char *s1, char *s2) {

    char s[100]// 保存拼接结果

    int i, j, k = 0

    for (i = 0s1[i] != '\0'++i) {

        s[k++] = s1[i]// 先复制s1中的1个字符

        for (j = 0s2[j] != '\0'++j)

            s[k++] = s2[j]// 再拼接整个s2

    }

    strcpy(s1, s)// 最后再将拼接好的s复制回s1

}

int main() {

    char s1[100] = "ABCD"

    char s2[100] = "*"

    join(s1, s2)

    printf("%s\n", s1)

    return 0

}

#include "stdafx.h"

#include "conio.h"

char *myfun(char *strA, char *strB, char strC)//strA用户数据，strB返回数据, strC插入字符

{

int m = 0

if (strA == NULL)

return NULL

int n = strlen(strA)

for (int i=0i<ni++)

{

strB[m]=strA[i]

if (strA[i]>= 0x30 &&strA[i]<= 0x39 )

{

strB[m+1] = strC

m += 1

}

m += 1

}

strB[m] = '\0'

return strB

}

main()

{

char p[] = "2m1f3d2de4wer5"

int k = strlen(p)

char *buff = (char *)malloc(k*2+1)

char *p1 = myfun(p, buff, 's')

printf("%s\n", p1)

free(buff)

}

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