python – 像Matlab一样在numpy中打印子数组

概述如何以与Matlab相同的方式打印numpy中的子阵列？我有一个3乘10000的数组,我想查看前20列.在Matlab中你可以写 a=zeros(3,10000);a(:,1:20) Columns 1 through 15 0 0 0 0 0 0 0 0 0 0 0 0 0 0 如何以与Matlab相同的方式打印numpy中的子阵列？我有一个3乘10000的数组,我想查看前20列.在Matlab中你可以写

a=zeros(3,10000);a(:,1:20)  Columns 1 through 15 0     0     0     0     0     0     0     0     0     0     0     0     0     0     0 0     0     0     0     0     0     0     0     0     0     0     0     0     0     0 0     0     0     0     0     0     0     0     0     0     0     0     0     0     0  Columns 16 through 20 0     0     0     0     0 0     0     0     0     0 0     0     0     0     0

然而在Numpy

import numpy as npset_printoptions(threshold=nan)a=np.zeros((3,10000))print a[:,0:20][[  0.   0.   0.   0.   0.   0.   0.   0.   0.   0.   0.   0.   0.   0.    0.   0.   0.   0.   0.   0.   0.   0.   0.   0.   0.   0.   0.   0.    0.   0.   0.   0.   0.   0.   0.   0.   0.   0.   0.   0.   0.   0.    0.   0.   0.   0.   0.   0.   0.   0.] [  0.   0.   0.   0.   0.   0.   0.   0.   0.   0.   0.   0.   0.   0.    0.   0.   0.   0.   0.   0.   0.   0.   0.   0.   0.   0.   0.   0.    0.   0.   0.   0.   0.   0.   0.   0.   0.   0.   0.   0.   0.   0.    0.   0.   0.   0.   0.   0.   0.   0.] [  0.   0.   0.   0.   0.   0.   0.   0.   0.   0.   0.   0.   0.   0.    0.   0.   0.   0.   0.   0.   0.   0.   0.   0.   0.   0.   0.   0.    0.   0.   0.   0.   0.   0.   0.   0.   0.   0.   0.   0.   0.   0.    0.   0.   0.   0.   0.   0.   0.   0.]]

如你所见,numpy打印第一行,然后是第二行,然后是第三行.我希望它保持列结构而不是行结构

非常感谢你

PS：例如,一种解决方案就是

print a[:,0:20].T[[  0.   0.   0.] [  0.   0.   0.] [  0.   0.   0.] [  0.   0.   0.] [  0.   0.   0.] [  0.   0.   0.] [  0.   0.   0.] [  0.   0.   0.] [  0.   0.   0.] [  0.   0.   0.] [  0.   0.   0.] [  0.   0.   0.] [  0.   0.   0.] [  0.   0.   0.] [  0.   0.   0.] [  0.   0.   0.] [  0.   0.   0.] [  0.   0.   0.] [  0.   0.   0.] [  0.   0.   0.]]

但是,屏幕上会消耗比预期更多的空间.如果numpy有这个选项会很棒

解决方法 这会给你想要的吗？

>>> for item in a[:,0:20].T:    print '\t'.join(map(str,item.toList()))

或这个？

>>> for item in a[:,0:20]:    print '\t'.join(map(str,item.toList()))

总结

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