增加函数中的案例编号？

概述我只是在学习C而且我在使用同一个printf函数增加dayName的代码时遇到了麻烦. 这是我的代码： #include <stdio.h>#define LENGH_OF_WEEK 7int main(){ int daysOfWeek[LENGH_OF_WEEK] = {0,1,2,3,4,5,6}; char* dayName = NULL;int i;for 我只是在学习C而且我在使用同一个printf函数增加dayname的代码时遇到了麻烦.

这是我的代码：

#include <stdio.h>#define LENGH_OF_WEEK 7int main(){    int daysOfWeek[LENGH_OF_WEEK] = {0,1,2,3,4,5,6};    char* dayname = NulL;int i;for (i = 0; i < LENGH_OF_WEEK; i++){    switch (daysOfWeek[i])    {    case 0: dayname = "Sunday"; break;    case 1: dayname = "Monday"; break;    case 2: dayname = "Tuesday"; break;    case 3: dayname = "Wednesday"; break;    case 4: dayname = "Thursday"; break;    case 5: dayname = "FrIDay"; break;    case 6: dayname = "Saturday"; break;    }    printf("%s,%s Happy Days\n",dayname,dayname);}return 0;}

正如你所看到的,我正试图让我的控制台唱出Happy Days,但它只是说dayname两次,我想弄清楚如何让它说“星期六,一整天！Groovin”整周与你同在！”案例6.

解决方法 这是我的经典主题曲的版本.抱歉,没有使用switch语句

#include <stdio.h>char *day[] = {"Sunday","Monday","Tuesday","Wednesday","Thursday","FrIDay","Saturday"};int main(){int i;for (i = 0; i < 5; i+=2){    printf("%s,day[i],day[i+1]);}printf("Saturday,what a day\n Groovin' all week with you!\n");return 0;}

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