public function testProductCreationFailsWhennameNotProvIDed(){ $product = factory(\App\Product::class)->make(['name' => '']); $this->post(route('API.products.store'),$product->JsonSerialize()) ->seeJson(['name' => ['The name fIEld is required.']]) /*line 86*/ ->assertResponseStatus(422);}
完整的错误报告在这里:
There was 1 error:1) ExampleTest::testProductCreationFailsWhennameNotProvIDedErrorException: InvalID argument supplIEd for foreach()C:\xampp\htdocs\product- service\vendor\laravel\framework\src\Illuminate\Support\Arr.PHP:494C:\xampp\htdocs\product-service\vendor\laravel\framework\src\Illuminate\Foundation\Testing\Concerns\MakeshttpRequests.PHP:231C:\xampp\htdocs\product-service\vendor\laravel\framework\src\Illuminate\Foundation\Testing\Concerns\MakeshttpRequests.PHP:257C:\xampp\htdocs\product-service\tests\ExampleTest.PHP:86C:\xampp\PHP\pear\PHPUnit\TextUI\Command.PHP:176C:\xampp\PHP\pear\PHPUnit\TextUI\Command.PHP:129FAILURES!Tests: 7,Assertions: 43,Errors: 1.
我承认这段代码原本不是我的 – 它是从Laravel教程复制的.它在那里工作得很好.
不幸的是,这个相关问题的答案也没有帮助我.
Laravel 5.1 + PHPunit – API test returns always invalid argument error foreach
我试图修改它以传递Json数组作为参数
public function testProductCreationFailsWhennameNotProvIDed() { $product = factory(\App\Product::class)->make(['name' => '']); $this->post(route('API.products.store'),$product->JsonSerialize()) ->seeJson(Json_encode(array('name' => ['The name fIEld is required.']))) ->assertResponseStatus(422); }
但后来我收到了这个错误:
1) ExampleTest::testProductCreationFailsWhennameNotProvIDedTypeError: Argument 1 passed to Illuminate\Foundation\Testing\TestCase::seeJson() must be of the type array,string given,called in C:\xampp\htdocs\product-service\tests\ExampleTest.PHP on line 86解决方法
1) ExampleTest::testProductCreationFailsWhennameNotProvIDed
TypeError: Argument 1 passed to Illuminate\Foundation\Testing\TestCase::seeJson() must be of the type array,called in C:\xampp\htdocs\product-service\tests\ExampleTest.PHP on line 86
此错误告诉您在此处传递了错误的类型:
->seeJson(Json_encode(array('name' => ['The name fIEld is required.'])))
你必须改变它看起来像这样,它应该工作.
->seeJson(array('name' => ['The name fIEld is required.']))总结
以上是内存溢出为你收集整理的Laravel 5.2 – 为foreach()提供的参数无效 – 使用phpunit全部内容,希望文章能够帮你解决Laravel 5.2 – 为foreach()提供的参数无效 – 使用phpunit所遇到的程序开发问题。
如果觉得内存溢出网站内容还不错,欢迎将内存溢出网站推荐给程序员好友。
欢迎分享,转载请注明来源:内存溢出
评论列表(0条)