perl6 – 不能在`qqww`或`qqww：to`结构中使用冒号对

概述我想使用Class生成一个json行,我会覆盖gist方法,以便它打印出我想要的内容： my $ak = '7111ac873c9dcd5fc335ded47630d050';my $st = '1523451601875';my $ifo = 'true';my $uu = "15778787898988090";class Stay { has $.ak is rw = '71 我想使用Class生成一个Json行,我会覆盖gist方法,以便它打印出我想要的内容：

my $ak = '7111ac873c9dcd5fc335ded47630d050';my $st = '1523451601875';my $ifo = 'true';my $uu = "15778787898988090";class Stay {  has $.ak  is rw = '7111ac873c9dcd5fc335ded47630d050';  has $.uu  is rw;  has $.ifo is rw;  has $.st  is rw;  method gist() {    #return qqww/{"ev":"app","ak":"$!ak","uu":"$!uu","ifo":"$!ifo","st":"$!st"}/;    return qqww:to「EOF」;    {"ev":"app","st":"$!st"}    EOF  }}say Stay.new(uu => $uu,ifo => $ifo,st => $st);

但失败了：

===SORRY!=== Error while compiling /Users/ohmycloud/Desktop/stay.pl6Confusedat /Users/ohmycloud/Desktop/stay.pl6:18------>     {"ev":⏏"app","ifo":"$!i    expecting any of:        colon pair

我想要的是：

{"ev":"app","ak":"7111ac873c9dcd5fc335ded47630d050","uu":"15778787898988090","ifo":"true","st":"1523451601875"}

为什么我不能在qqww或qq中使用冒号对：结构？

解决方法 你可以使用 unquoting：

method gist() {    return '{"ev":"app","ak":"\qq[$!ak]","uu":"\qq[$!uu]","ifo":"\qq[$!ifo]","st":"\qq[$!st]"}':}

将返回

{"ev":"app","st":"1523451601875"}

如果你使用qqww或类似的话,冒号会妨碍你.

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