ruby – 使用字符串到文件名

概述我正在尝试从字符串中输入文件名,但不能. 这很好用： #!/usr/bin/rubyrequire 'httpclient'http2 = HTTPClient.newresponse = http2.get_content("http://example.com/version.ini")response.each_line do | line | http = HTTPC 我正在尝试从字符串中输入文件名,但不能.

这很好用：

@H_502_13@#!/usr/bin/rubyrequire 'httpclIEnt'http2 = httpClIEnt.newresponse = http2.get_content("http://example.com/version.ini")response.each_line do | line | http = httpClIEnt.new my_file = open('file.zip','wb') my_file.write(http.get_content("http://example.com/data.zip"))endputs "Done."

但这不是：

@H_502_13@#!/usr/bin/rubyrequire 'httpclIEnt'http2 = httpClIEnt.newresponse = http2.get_content("http://example.com/version.ini")response.each_line do | line | puts line # -> file.zip http = httpClIEnt.new my_file = open(line,'wb') my_file.write(http.get_content("http://example.com/data.zip"))endputs "Done."

安慰：

C:/Ruby22-x64/lib/ruby/2.2.0/open-uri.rb:36:in initialize': InvalID
argument @ rb_sysopen - file.zip (Errno::EINVAL)
from C:/Ruby22-x64/lib/ruby/2.2.0/open-uri.rb:36:inopen’
from C:/Ruby22-x64/lib/ruby/2.2.0/open-uri.rb:36:in open'
from launcher.rb:10:inblock in ‘
from launcher.rb:7:in each_line'
from launcher.rb:7:in‘

解决方法 问题是使用换行符char,尝试剥离它.

@H_502_13@my_file = open(line.chomp,'wb') 总结

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