C语言将16进制字符数组转为字符串

比如我们收到一包数据，数据为十六进制数（0xA1,0xB1,0xC1,0xD1），结果是：将此十六进制数据转换为字符串“A1B1C1D1”。用途：写日志或者其他特殊用法。方便用%s打印出来查看

#define u8   unsigned char
#define u32   unsigned int

int main()
{
	unsigned char SN[6] = { 0x00,0x00,0x00,0x00,0x57,0xe4 };
	
	unsigned char sn[6];
	hex_to_asciistring(SN, 6, sn);
	
	printf("SN=%s\n,",sn);//输出结果为“0000000057e4”

}

//参数1为原始数据，参数2为数组长度，参数三为转出来的字符串
void hex_to_asciistring(u8* str,u32 size,u8* str1)
{
	u8 deposit [2];
	int i=0;
	u8 j = 0;
 
	for(i=0;i<size;i++)
	{
 
		deposit[1] = str[i] & 0x0F;
		deposit[0] = (str[i] &0xF0) >> 4;
		for(j = 0; j < 2; j++)
		{
		switch(deposit[j])
		{
			case 0x00:
			  str1[i*2+j]='0';
				break;
			case 0x01:
			  str1[i*2+j]='1';
				break;
			case 0x02:
			  str1[i*2+j]='2';
				break;
			case 0x03:
			  str1[i*2+j]='3';
				break;
			case 0x04:
			 str1[i*2+j]='4';
				break;
			case 0x05:
			  str1[i*2+j]='5';
				break;
			case 0x06:
			  str1[i*2+j]='6';
				break;
			case 0x07:
			  str1[i*2+j]='7';
				break;
			case 0x08:
			  str1[i*2+j]='8';
				break;
			case 0x09:
			  str1[i*2+j]='9';
				break;
			case 0x0A:
			  str1[i*2+j]='A';
				break;
			case 0x0B:
			  str1[i*2+j]='B';
				break;
			case 0x0C:
			  str1[i*2+j]='C';
				break;
			case 0x0D:
			  str1[i*2+j]='D';
				break;
			case 0x0E:
			  str1[i*2+j]='E';
				break;
			case 0x0F:
			  str1[i*2+j]='F';
				break;
			default:
				return ;
		}
 
	}
 
	}
   return ;
}