c语言程序设计第五版第三章课后习题

代码仅供参考，有错望提醒

	//1
	//double p = 1, r = 0.07;
	//int n = 10;
	//p = pow((1 + 0.07), n) - 1;
	//printf("%.2f%%",p);


	//2
	//double p1 = 0.015, p2 = 0.021, p3 = 0.0275, p4 = 0.03, p5 = 0.0035;
	//double count;

	//printf("（1）种存款五年后本息为%f\n", count = 1000 * (1 + 5 * p4));
	//printf("（2）种存款五年后本息为%f\n", count = (1000 * (1 + 2 * p2)) * (1 + 3 * p3));
	//printf("（3）种存款五年后本息为%f\n", count = (1000 * (1 + 3 * p3)) * (1 + 2 * p2));
	//printf("（4）种存款五年后本息为%f\n", count = 1000 * (pow((1 + p1), 5)));
	//printf("（5）种存款五年后本息为%f\n", count = 1000 * (pow((1 + p5 / 4), 20)));


	//3
	//double d = 300000.0, p = 6000.0, r = 0.01;
	//double m;
	//m = log10(p / (p - d * r)) / log10(1 + r);
	//printf("%.1f",m);

	//6
	//char c1, c2, c3, c4, c5;
	//c1 = getchar();
	//c2 = getchar();
	//c3 = getchar();
	//c4 = getchar();
	//c5 = getchar();

	//c1 += 4;
	//c2 += 4;
	//c3 += 4;
	//c4 += 4;
	//c5 += 4;

	//putchar(c1);
	//putchar(c2);
	//putchar(c3);
	//putchar(c4);
	//putchar(c5);
	//printf("\n");

	//printf("%c", c1);
	//printf("%c", c2);
	//printf("%c", c3);
	//printf("%c", c4);
	//printf("%c", c5);
	//printf("\n");



	//7
	//double r = 1.5, p = 3.14;
	//int h = 3;
	//double c, s, s1, v1, v2;
	//printf("圆周长为:%.2f\n", c = 2 * r * p);
	//printf("圆面积为:%.2f\n", s = p * sqrt(r));
	//printf("圆球表面积为:%.2f\n", s1 = 4 * p * sqrt(r));
	//printf("圆球体积为:%.2f\n", v1 = 4 * p * pow(r, 3) / 3);
	//printf("圆柱体积为:%.2f\n", v2 = s * h);
	

调用了数学函数的需要加一个

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