那么,以 2015-01-01为起始日,每5天累总计数为:
select datediff(dt, '2015-01-01') div 5 as d5 , count(*)
from ta
group by (datediff(dt, '2015-01-01') div 5)
欢迎分享,转载请注明来源:内存溢出
那么,以 2015-01-01为起始日,每5天累总计数为:
select datediff(dt, '2015-01-01') div 5 as d5 , count(*)
from ta
group by (datediff(dt, '2015-01-01') div 5)
欢迎分享,转载请注明来源:内存溢出
评论列表(0条)