我试图选择表中的所有内容,并计算表中具有相同数据的行数.
SELECT *,COUNT(thedate) daycount FROM `table` ORDER BY thedate DESC
我希望有一个查询输出与该日期相关的日期和行数,循环输出将是这样的:
Jan 1,2000 (2 rows)
col1,col2,col3,col4
col1,col4Jan 1,2000 (3 rows)
col1,2000 (6 rows)
col1,col4
等等…
这有意义吗?
最佳答案如果您有一个如下所示的表:CREATE table yourtable( datefIEld DATETIME,col1 VARCHAR(20),col2 INT NOT NulL,col3 tinyint NOT NulL,col4 CHAR(5));
并且您希望每个给定日期重复col1 .. col4的计数,您将运行此查询
SELECT COUNT(datefIEld) datefIEld_count,left(all_fIElds,10) datefIEld,SUBSTR(all_fIElds,11) all_other_fIEldsFROM( SELECT DATE(datefIEld) datefIEld,CONCAT(DATE(datefIEld),'|',COALESCE(col1,'< NulL >'),COALESCE(col2,COALESCE(col3,COALESCE(col4,'|') all_fIElds FROM yourtable) AGROUP BY all_fIElds;
以下是一些示例数据和查询结果:
MysqL> DROP table IF EXISTS yourtable;query OK,0 rows affected (0.04 sec)MysqL> CREATE table yourtable -> ( -> datefIEld DATETIME,-> col1 VARCHAR(20),-> col2 INT,-> col3 tinyint,-> col4 CHAR(5) -> );query OK,0 rows affected (0.11 sec)MysqL> INSERT INTO yourtable VALUES -> (DATE(Now() - INTERVAL 1 DAY),'rolando',4,3,'angel'),-> (DATE(Now() - INTERVAL 1 DAY),NulL,-> (DATE(Now() - INTERVAL 2 DAY),2,'eDWards'),-> (DATE(Now() - INTERVAL 3 DAY),5,'pamela','angel') -> ;query OK,22 rows affected,3 warnings (0.03 sec)Records: 22 Duplicates: 0 Warnings: 3MysqL> SELECT * FROM yourtable;+---------------------+---------+------+------+-------+| datefIEld | col1 | col2 | col3 | col4 |+---------------------+---------+------+------+-------+| 2011-06-30 00:00:00 | rolando | 4 | 3 | angel || 2011-06-30 00:00:00 | rolando | 4 | 3 | angel || 2011-06-30 00:00:00 | rolando | 4 | 3 | angel || 2011-06-30 00:00:00 | rolando | 4 | NulL | angel || 2011-06-30 00:00:00 | rolando | 4 | NulL | angel || 2011-06-29 00:00:00 | rolando | 4 | 2 | angel || 2011-06-29 00:00:00 | rolando | 4 | 2 | angel || 2011-06-29 00:00:00 | rolando | 4 | 2 | angel || 2011-06-29 00:00:00 | rolando | 4 | 2 | angel || 2011-06-29 00:00:00 | rolando | 4 | NulL | eDWar || 2011-06-29 00:00:00 | rolando | 4 | NulL | angel || 2011-06-28 00:00:00 | rolando | 5 | 2 | angel || 2011-06-28 00:00:00 | rolando | 5 | 2 | angel || 2011-06-28 00:00:00 | rolando | 4 | 2 | angel || 2011-06-28 00:00:00 | pamela | 4 | 2 | angel || 2011-06-28 00:00:00 | pamela | 4 | NulL | eDWar || 2011-06-28 00:00:00 | pamela | 5 | 2 | angel || 2011-06-28 00:00:00 | pamela | 5 | 2 | angel || 2011-06-28 00:00:00 | rolando | 4 | 2 | angel || 2011-06-28 00:00:00 | rolando | 4 | 2 | angel || 2011-06-28 00:00:00 | rolando | 4 | NulL | eDWar || 2011-06-28 00:00:00 | rolando | 4 | NulL | angel |+---------------------+---------+------+------+-------+22 rows in set (0.00 sec)MysqL> SELECT -> COUNT(datefIEld) datefIEld_count,-> left(all_fIElds,-> SUBSTR(all_fIElds,11) all_other_fIElds -> FROM -> ( -> SELECT -> DATE(datefIEld) datefIEld,-> CONCAT(DATE(datefIEld),-> COALESCE(col1,-> COALESCE(col2,-> COALESCE(col3,-> COALESCE(col4,'|') all_fIElds -> FROM -> yourtable -> ) A -> GROUP BY all_fIElds;+-----------------+------------+----------------------------+| datefIEld_count | datefIEld | all_other_fIElds |+-----------------+------------+----------------------------+| 1 | 2011-06-28 | |pamela|4|2|angel| || 1 | 2011-06-28 | |pamela|4|< NulL >|eDWar| || 2 | 2011-06-28 | |pamela|5|2|angel| || 3 | 2011-06-28 | |rolando|4|2|angel| || 1 | 2011-06-28 | |rolando|4|< NulL >|angel| || 1 | 2011-06-28 | |rolando|4|< NulL >|eDWar| || 2 | 2011-06-28 | |rolando|5|2|angel| || 4 | 2011-06-29 | |rolando|4|2|angel| || 1 | 2011-06-29 | |rolando|4|< NulL >|angel| || 1 | 2011-06-29 | |rolando|4|< NulL >|eDWar| || 3 | 2011-06-30 | |rolando|4|3|angel| || 2 | 2011-06-30 | |rolando|4|< NulL >|angel| |+-----------------+------------+----------------------------+12 rows in set (0.00 sec)MysqL>
我会留给你富有想象力的创造力来循环阅读和打印
> datefIEld
> datefIEld_count
>打印all_other_fIElds’datefIEld_count’次
试试看 !!! 总结
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