目录下面有几十万的文件，有什么技术可以很快的轮询，最好能用java实现的

import java.io.File

import java.util.ArrayList

public class FileSystem1 {

private static ArrayList filelist = new ArrayList()

public static void main(String[] args) {

long a = System.currentTimeMillis()

refreshFileList("c:\\java")

System.out.println(System.currentTimeMillis() - a)

}

public static void refreshFileList(String strPath) {

File dir = new File(strPath)

File[] files = dir.listFiles()

if (files == null) return

for (int i = 0i <files.lengthi++) {

if (files[i].isDirectory()) {

refreshFileList(files[i].getAbsolutePath())

}

else

{ String strFileName = files[i].getAbsolutePath().toLowerCase()

System.out.println("---"+strFileName)

filelist.add(files[i].getAbsolutePath())

}

}

}

}

这是递归遍历方式

或者 你可以用java 调用微软cmd命令 用java来接收返回的结果

if ($kind != 'ReplyTo') {

if (!isset($this->all_recipients[strtolower($address)])) {

array_push($this->$kind, array($address, $name))

$this->all_recipients[strtolower($address)] = true

return true

}

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