update A.search s join B.room r on s.room_id=r.room_id
set s.is_online=r.is_online
不过你这room如果只有几条,直接把is_online对应room_id的值写在sql里去更新A.search表不就好了
update A.search set is_online=(case when room_id=x1 then y1 when room_id=x2
then y2 when room_id=x3 then y3 ...... else yn end)
1、where型子查询#不用order by 来查询最新的商品
select goods_id,goods_name from goods where goods_id = (select max(goods_id) from goods)
#取出每个栏目下最新的产品(goods_id唯一)
select cat_id,goods_id,goods_name from goods where goods_id in(select max(goods_id) from goods group by cat_id)
2、from型子查询
(把内层的查询结果供外层再次查询)
#用子查询查出挂科两门及以上的同学的平均成绩
思路:
#先查出哪些同学挂科两门以上
select name,count(*) as gk from stu where score <60 having gk >=2
#以上查询结果,我们只要名字就可以了,所以再取一次名字
select name from (select name,count(*) as gk from stu having gk >=2) as t
#找出这些同学了,那么再计算他们的平均分
select name,avg(score) from stu where name in (select name from (select name,count(*) as gk from stu having gk >=2) as t) group by name
3、exists型子查询
(把外层查询结果拿到内层,看内层的查询是否成立)
#查询哪些栏目下有商品,栏目表category,商品表goods
select cat_id,cat_name from category where exists(select * from goods where goods.cat_id = category.cat_id)
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