java中怎么把文件上传到服务器的指定路径？

文件从本地到服务器的功能，其实是为了解决目前浏览器不支持获取本地文件全路径。不得已而想到上传到服务器的固定目录，从而方便项目获取文件，进而使程序支持EXCEL批量导入数据。

java中文件上传到服务器的指定路径的代码：

在前台界面中输入：

<form method="post" enctype="multipart/form-data"  action="../manage/excelImport.do">

请选文件:<input type="file"  name="excelFile">

<input type="submit" value="导入" onclick="return impExcel()"/>

</form>

action中获取前台传来数据并保存

/**

* excel 导入文件

* @return

* @throws IOException

*/

@RequestMapping("/usermanager/excelImport.do")

public String excelImport(

String filePath,

MultipartFile  excelFile,HttpServletRequest request) throws IOException{

log.info("<<<<<<action:{} Method:{} start>>>>>>","usermanager","excelImport" )

if (excelFile != null){

String filename=excelFile.getOriginalFilename()

String a=request.getRealPath("u/cms/www/201509")

SaveFileFromInputStream(excelFile.getInputStream(),request.getRealPath("u/cms/www/201509"),filename)//保存到服务器的路径

}

log.info("<<<<<<action:{} Method:{} end>>>>>>","usermanager","excelImport" )

return ""

}

/**

* 将MultipartFile转化为file并保存到服务器上的某地

*/

public void SaveFileFromInputStream(InputStream stream,String path,String savefile) throws IOException

{    

FileOutputStream fs=new FileOutputStream( path + "/"+ savefile)

System.out.println("------------"+path + "/"+ savefile)

byte[] buffer =new byte[1024*1024]

int bytesum = 0

int byteread = 0

while ((byteread=stream.read(buffer))!=-1)

{

bytesum+=byteread

fs.write(buffer,0,byteread)

fs.flush()

}

fs.close()

stream.close()

}

1、首先将java项目通过解析request，并设置上传路径。

2、其次分配好电脑上传路径后，创建一个迭代器。

最后通过迭代器进行判空，再通过循环来实现多个文件的上传，再输出文件信息的同时上传多个系统即可。

servlet类

package org.whatisjava.servlet

import java.io.File

import java.io.IOException

import java.util.List

import javax.servlet.ServletContext

import javax.servlet.ServletException

import javax.servlet.http.HttpServlet

import javax.servlet.http.HttpServletRequest

import javax.servlet.http.HttpServletResponse

import org.apache.commons.fileupload.FileItem

import org.apache.commons.fileupload.disk.DiskFileItemFactory

import org.apache.commons.fileupload.servlet.ServletFileUpload

public class UploadServlet extends HttpServlet {

public void service(HttpServletRequest request, HttpServletResponse response)

throws ServletException, IOException {

try {

// 用于设定诸如缓存之类的参数，和性能相关

// 此处用默认设定

DiskFileItemFactory dfif = new DiskFileItemFactory()

// 解析表单中的数据

ServletFileUpload upload = new ServletFileUpload(dfif)

upload.setSizeMax(10 * 1024 * 1024)// 允许上传的最大值

List list = upload.parseRequest(request)// 开始解析request对象中的表单数据

// list中是FileItem对象

// 一个FileItem用于封装一个上传的文件数据

if (list.size() >= 1) {

FileItem item = (FileItem) list.get(0)

// 获得上文件的路径名

String name = item.getName()

name = name.substring(name.lastIndexOf("\\") + 1)

// 把上传的文件数据写入本地文（服务器端）件文件夹的名字为upload

String path = "upload"

// Sun的标准，服务器实现的API

ServletContext ctx = this.getServletContext()

path = ctx.getRealPath(path)

File file = new File(path)

if(!file.exists()){

System.out.println("创建文件夹")

file.mkdir()

}

System.out.println(path)

System.out.println(name)

//将文件放到指定的地方

item.write(new File(path, name))

response.sendRedirect("upload_form.jsp")

}

} catch (Exception e) {

throw new ServletException("file upload error!", e)

}

}

}

页面<form action="upload" method="post" enctype="multipart/form-data">

<table cellpadding="0" cellspacing="0" border="0"

class="form_table">

<tr>

<td valign="middle" align="right">

上传

</td>

<td valign="middle" align="left">

<input type="file" class="inputgri" name="file1" />

</td>

</tr>

</table>

<p>

<input type="submit" class="button" value="提交 »" />

</p>

</form>

web.xml

<servlet>

<servlet-name>UploadServlet</servlet-name>

<servlet-class>

org.whatisjava.servlet.UploadServlet

</servlet-class>

</servlet>

<servlet-mapping>

<servlet-name>UploadServlet</servlet-name>

<url-pattern>/upload</url-pattern>

</servlet-mapping>

jar包

commons-io-1.3.2.jar

commons-fileupload-1.2.1.jar

commons-fileupload-1.2.1-javadoc.jar

commons-fileupload-1.2.1-sources.jar

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