在Swift 2中实现时间帧的方法

概述这是自助餐厅的营业时间 Monday - Thursday: 10:30 am - 12:00 amFriday: 10:30 am - 9:00 pm Saturday - Sunday: Closed 我正在实现一个函数,如果该地点根据当前时间打开或关闭,则返回一个状态. 在没有处理复杂的“if”语句的情况下,是否有更简单,更有效的方法来实现这样的事情？ func displayStatu 这是自助餐厅的营业时间

Monday - Thursday: 10:30 am - 12:00 amFrIDay: 10:30 am - 9:00 pm Saturday - Sunday: Closed

我正在实现一个函数,如果该地点根据当前时间打开或关闭,则返回一个状态.
在没有处理复杂的“if”语句的情况下,是否有更简单,更有效的方法来实现这样的事情？

func displayStatusForBrandywine () -> String    {         let currentDateTime = NSDate()        // get the user's calendar        let userCalendar = NSCalendar.currentCalendar()        // choose which date and time components are needed        let requestedComponents: NSCalendarUnit = [            NSCalendarUnit.Year,NSCalendarUnit.Month,NSCalendarUnit.Day,NSCalendarUnit.Hour,NSCalendarUnit.Minute,NSCalendarUnit.Weekday        ]        // get the components        let dateTimeComponents = userCalendar.components(requestedComponents,fromDate: currentDateTime)        var status: String = ""        if ((dateTimeComponents.weekday >= 2 && dateTimeComponents.weekday <= 5) && (dateTimeComponents.hour >= 10 && dateTimeComponents.hour <= 23) && (dateTimeComponents.minute <= 59 && dateTimeComponents.hour != 0) || ((dateTimeComponents.weekday == 6 && dateTimeComponents.hour >= 10 && dateTimeComponents.minute >= 30 && dateTimeComponents.hour <= 21) || (dateTimeComponents.weekday == 6 && dateTimeComponents.hour >= 11 && (dateTimeComponents.hour <= 21 && dateTimeComponents.minute < 0))))        {            status = "Open"        }        else        {            status = "Closed"        }        return status    }

解决方法 这是一个有趣的方式来做到这一点……

struct OpenPeriod {    var day: Int    var openTime: Double    var closeTime: Double    func isOpen(dateTime: NSDate) -> Bool {        let userCalendar = NSCalendar.currentCalendar()        // choose which date and time components are needed        let requestedComponents: NSCalendarUnit = [            NSCalendarUnit.Hour,fromDate: dateTime)        if dateTimeComponents.weekday != self.day { return false }        let timeOfDay = Double(dateTimeComponents.hour) + Double(dateTimeComponents.minute) / 60        return timeOfDay >= self.openTime && timeOfDay <= self.closeTime    }}var openingTimes = [OpenPeriod]()openingTimes.append(OpenPeriod(day: 2,openTime: 10.5,closeTime: 12))openingTimes.append(OpenPeriod(day: 3,closeTime: 12))openingTimes.append(OpenPeriod(day: 4,closeTime: 12))openingTimes.append(OpenPeriod(day: 5,closeTime: 21))func open(dateTime: NSDate) -> Bool {    return openingTimes.reduce(true,combine: {  && .isOpen(dateTime) })}open(NSDate()) ? "Open" : "Closed"

总结

以上是内存溢出为你收集整理的在Swift 2中实现时间帧的方法全部内容，希望文章能够帮你解决在Swift 2中实现时间帧的方法所遇到的程序开发问题。

如果觉得内存溢出网站内容还不错，欢迎将内存溢出网站推荐给程序员好友。