我有一个encodable的扩展来创建一个字典:
extension encodable { var dictionary: [String: Any] { return (try? JsONSerialization.JsonObject(with: JsONEncoder().encode(self),options: .allowFragments)) as? [String: Any] ?? [:] }}
然后在协议扩展中,我将记录创建为属性,如果类型为Data,我尝试创建CKAsset.
var ckEncoded: CKRecord? { // Convert self.ID to CKRecord.name (CKRecordID) guard let IDString = self.ID?.uuIDString else { return nil } let record = CKRecord(recordtype: Self.entityType.rawValue,recordID: CKRecordID(recordname: IDString)) self.dictionary.forEach { if let data =func decode(_ ckRecord: CKRecord) throws { let keyIntersection = Set(self.dtoEncoded.dictionary.keys).intersection(ckRecord.allKeys()) var dictionary: [String: Any?] = [:] keyIntersection.forEach { if let asset = ckRecord[.value as? Data { if let asset: CKAsset = try? ckAsset(from: data,ID: IDString) { record[.key] = asset } } else { record[.key] = .value as? CKRecordValue } } return record}/// Returns CKRecordfunc ckRecord() -> CKRecord { let record = CKRecord(recordtype: "MyClasstype") record["Title"] = Title as CKRecordValue record["color"] = color as CKRecordValue return record}init(withRecord record: CKRecord) { Title = record["Title"] as? String ?? "" color = record["color"] as? String ?? kDefaultcolor}] as? CKAsset { dictionary[] = try? self.data(from: asset) } else { dictionary[] = ckRecord[] } } guard let data = try? JsONSerialization.data(withJsONObject: dictionary) else { throw Errors.LocalData.isCorrupted } guard let dto = try? JsONDecoder().decode(self.DTO,from: data) else { throw Errors.LocalData.isCorrupted } do { try decode(dto) } catch { throw error }}
要解码:
除数据类型外,所有内容都可以正常工作.它无法从字典中识别出来.所以,我无法将其转换为CKAsset.先感谢您.
解决方法 我还发现到目前为止苹果还没有对此提供干净的支持.我的解决方案是手动编码/解码:在我的Codable子类上,我添加了两个方法:
针对更复杂案例的另一个解决方案是使用一些第三方库,我遇到的是:https://github.com/insidegui/CloudKitCodable
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