For an undirected graph with tree characteristics,we can choose any node as the root. The result graph is then a rooted tree. Among all possible rooted trees,those with minimum height are called minimum height trees (MHTs). Given such a graph,write a function to find all the MHTs and return a List of their root labels.
Format
The graph contains n
nodes which are labeled from 0
to n - 1
. You will be given the number n
and a List of undirected edges
(each edge is a pair of labels).
You can assume that no duplicate edges will appear in edges
. Since all edges are undirected, [0,1]
is the same as [1,0]
and thus will not appear together in edges
.
Example 1 :
input:,0 | 1 / 2 3 Output: n = 4edges = [[1,0],[1,2],3]][1]
Example 2 :
input:,0 1 2 \ | / 3 | 4 | 5 Output: n = 6edges = [[0,3],[2,[4,[5,4]][3,4]
Note:
According to the definition of tree on Wikipedia: “a tree is an undirected graph in which any two vertices are connected by exactly one path. In other words,any connected graph without simple cycles is a tree.” The height of a rooted tree is the number of edges on the longest downward path between the root and a leaf.对于一个具有树特征的无向图,我们可选择任何一个节点作为根。图因此可以成为树,在所有可能的树中,具有最小高度的树被称为最小高度树。给出这样的一个图,写出一个函数找到所有的最小高度树并返回他们的根节点。
格式
该图包含 n
个节点,标记为 0
到 n - 1
。给定数字 n
和一个无向边 edges
列表(每一个边都是一对标签)。
你可以假设没有重复的边会出现在 edges
中。由于所有的边都是无向边, [0,1]
和 [1,0]
是相同的,因此不会同时出现在 edges
里。
示例 1:
输入:,0 | 1 / 2 3 输出: n = 4edges = [[1,3]][1]
示例 2:
输入:,0 1 2 \ | / 3 | 4 | 5 输出: n = 6edges = [[0,4]
说明:
根据树的定义,树是一个无向图,其中任何两个顶点只通过一条路径连接。 换句话说,一个任何没有简单环路的连通图都是一棵树。 树的高度是指根节点和叶子节点之间最长向下路径上边的数量。1724 ms
1 class Solution { 2 func findMinHeightTrees(_ n: Int,_ edges: [[Int]]) -> [Int]{ 3 var graph = [Int : Set<Int>]() 4 for edge in edges { 5 if graph[edge[0]] == nil { 6 graph[edge[0]] = [edge[1]] 7 }else { 8 graph[edge[0]]!.insert(edge[1]) 9 }10 if graph[edge[1]] == nil {11 graph[edge[1]] = [edge[0]]12 }else {13 graph[edge[1]]!.insert(edge[0])14 }15 16 }17 while graph.count > 2 {18 let List = graph.filter{$1.count == 1}19 for dict in List {20 graph[dict.value.first!]?.remove(dict.key)21 graph[dict.key] = nil22 }23 }24 25 let res = Array(graph.keys)26 if res.isEmpty {27 return [0]28 }29 return res30 }31 }总结
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