ios – “无法递增endIndex” – 由于UITextView中的表情符号字符而出错

概述我有UITextView的扩展： extension UITextView { func separatedWordsInFrontCursor(infront: Bool = true) -> [String] { let cursorPosition = selectedRange.location let separationCharacters 我有UITextVIEw的扩展：

extension UITextVIEw {    func separateDWordsInFrontCursor(infront: Bool = true) -> [String] {        let cursorposition = selectedRange.location        let separationCharacters = NSCharacterSet(charactersInString: " ")        let beginRange = Range(start: text.startIndex.advancedBy(0),end: text.startIndex.advancedBy(cursorposition))        //Fatal error: can not increment endindex        let endRange = Range(start: text.startIndex.advancedBy(cursorposition),end: text.startIndex.advancedBy(text.characters.count))        let beginPhrase = text.substringWithRange(beginRange)        let endPhrase = text.substringWithRange(endRange)        return infront ? beginPhrase.componentsSeparatedByCharactersInSet(separationCharacters) : endPhrase.componentsSeparatedByCharactersInSet(separationCharacters)    }}

错误如下：

Fatal error: can not increment endindex

这是我尝试输入UITextVIEw：

UITextVIEw的键盘类型设置为“默认”.

出现错误时：

cursorposition is 3text.characters.count is 2text.startIndex is 0text.startIndex.advancedBy(2) is 3text.startIndex.advancedBy(cursorposition) is "Fatal error: can not increment endindex"

我该如何解决这个问题？

解决方法 正如@Martin R所说,我们需要对NSRange和Nsstring进行 *** 作,因此解决方案如下：

private func separateDWordsInFrontCursor(infront: Bool = true) -> [String] {    let cursorposition = selectedRange.location    let separationCharacters = NSCharacterSet(charactersInString: " ")    let nstext = Nsstring(string: text)    let beginRange = NSRange(location: 0,length: cursorposition)    let endRange = NSRange(location: cursorposition,length: nstext.length - cursorposition)    let beginPhrase = nstext.substringWithRange(beginRange)    let endPhrase = nstext.substringWithRange(endRange)    return infront ? beginPhrase.componentsSeparatedByCharactersInSet(separationCharacters) : endPhrase.componentsSeparatedByCharactersInSet(separationCharacters)}

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