ios – 使用CCHmac()生成HMAC swift sdk8.3

概述在SDK8.3之前我用这种方式生成了我的hmac.现在我在CCHmac()函数上出错了.由于我是初学者,我无法弄清楚如何解决它.在此先感谢您的帮助！ xcode warning: cannot involke ‘CCHmac’ with an argument list of type (UInt32, [CChar]?, UInt, [CChar]?, UInt, inout[(CUnsigne @H_404_6@ 在SDK8.3之前我用这种方式生成了我的hmac.现在我在CCHmac()函数上出错了.由于我是初学者,我无法弄清楚如何解决它.在此先感谢您的帮助！

xcode warning: cannot involke ‘CCHmac’ with an argument List of type (UInt32,[CChar]?,UInt,inout[(CUnsignedChar)]

func generateHMAC(key: String,data: String) -> String {    let cKey = key.cStringUsingEnCoding(NSUTF8StringEnCoding)    let cdata = data.cStringUsingEnCoding(NSUTF8StringEnCoding)    var result = [CUnsignedChar](count: Int(CC_SHA512_DIGEST_LENGTH),repeatedValue: 0)    CCHmac(CCHmacAlgorithm(kCCHmacAlgSHA512),cKey,strlen(cKey!),cdata,strlen(cdata!),&result)    let hash = NSMutableString()    for var i = 0; i < result.count; i++ {        hash.appendFormat("%02hhx",result[i])    }    return hash as String}

解决方法 问题是strlen返回一个UInt,而CCHmac的长度参数是Ints.

虽然你可以做一些强制,你也可以只使用两个数组的count属性而不是调用strlen.

func generateHMAC(key: String,data: String) -> String {    var result: [CUnsignedChar]    if let cKey = key.cStringUsingEnCoding(NSUTF8StringEnCoding),cdata = data.cStringUsingEnCoding(NSUTF8StringEnCoding)    {        let algo  = CCHmacAlgorithm(kCCHmacAlgSHA512)        result = Array(count: Int(CC_SHA512_DIGEST_LENGTH),repeatedValue: 0)        CCHmac(algo,cKey.count-1,cdata.count-1,&result)    }    else {        // as @MartinR points out,this is in theory impossible         // but personally,I prefer doing this to using `!`        fatalError("Nil returned when processing input strings as UTF8")    }    let hash = NSMutableString()    for val in result {        hash.appendFormat("%02hhx",val)    }    return hash as String}

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