java-twitter4j找不到身份验证挑战

概述一直试图使用twitter4j发布推文已有两天了,但是没有运气,我想做的是一个人在回合结束时从应用程序在其时间轴上发布其新的最高分.这是我的代码@OverrideprotectedvoidonCreate(BundlesavedInstanceState){super.onCreate(savedInstanceState);setConten

一直试图使用twitter4j发布推文已有两天了,但是没有运气,我想做的是一个人在回合结束时从应用程序在其时间轴上发布其新的最高分.这是我的代码

          @OverrIDeprotected voID onCreate(Bundle savedInstanceState) {    super.onCreate(savedInstanceState);    setContentVIEw(R.layout.activity_tweetr);    button tweetr = (button)findVIEwByID(R.ID.tweetr);    //create a new twitter configuration using user details    tweetTwitter = new TwitterFactory().getInstance();    tweetTwitter.setoAuthConsumer(TWIT_KEY, TWIT_SECRET);        //create a twitter instance   // tweetTwitter = new TwitterFactory(twitConf).getInstance();    tweetr.setonClickListener(new VIEw.OnClickListener() {        @OverrIDe        public voID onClick(VIEw v) {          dt.execute();        }    });}public class TweetTask extends AsyncTask<Object, VoID, String> {    @OverrIDe    protected String doInBackground(Object... values) {        /* try {            //requestToken = tweetTwitter.getoAuthRequestToken(TWITTER_CALLBACK_URL);        } catch (TwitterException e) {            // Todo auto-generated catch block            e.printstacktrace();        }        startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse(requestToken.getAuthenticationURL())));        */        try {            requestToken = tweetTwitter.getoAuthRequestToken(TWITTER_CALLBACK_URL);            String authUrl = requestToken.getAuthenticationURL();            startActivity(new Intent(Intent.ACTION_VIEW, Uri.parse(authUrl)));        } catch (TwitterException e) {            // Todo auto-generated catch block            e.printstacktrace();        }      return null;    }    @OverrIDe    protected voID onPostExecute(String result) {        Log.d("URI", "DONE");        super.onPostExecute(result);    }}@OverrIDeprotected voID onResume() {    super.onResume();    final Uri uri = getIntent().getData();    if(uri != null ){                Log.d("URI", uri.toString());                Thread th = new Thread(){                    public voID run(){                        try {                            String verifIEr = uri.getqueryParameter("oauth_verifIEr");                            String oauthToken = uri.getqueryParameter("oauth_token");                            RequestToken reqToken = tweetTwitter.getoAuthRequestToken(oauthToken,verifIEr);                             Accesstoken accesstoken = tweetTwitter.getoAuthAccesstoken(reqToken);                            String token = accesstoken.getToken(), secret = accesstoken.getTokenSecret();                        } catch (TwitterException ex) {                            Log.e("Main.onNewIntent", "" + ex.getMessage());                        }                    }};                    th.start();      }else        Log.d("URI", "Failed");             }

}

这是我的错误打印出来

10-23 15:35:18.661: D/TWIT ER(2392): No authentication challenges foundRelevant discussions can be found on the Internet at:

解决方法:

参考Twitter4J的javadoc

In order to get access acquire Accesstoken using xAuth, you must apply by sending an email to [email protected] — all other applications will receive an http 401 error.

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