java– 如何解析JSON字符串Android

概述我正在尝试解析下面的JSONString[[{"0":"","title":"TechnicalSupportAnalystinNoida","1":"","CompanyName":"Oracle","2":"","Category":"Fresher&

我正在尝试解析下面的JSONString

[[{"0":"","Title":" Technical Support Analyst in NoIDa","1":"","Company name":" Oracle","2":"","category":"Fresher","3":"","Job Type":"Full Time","4":"","Location":"NoIDa","5":"","Job Qualification":"BE\/BTch\/Bsc\/Others","6":"","Job ExperIEnce":"Freshers","7":"","Job postdate":"2013-6-05","8":""}]]

我的代码：

// try parse the string to a JsON objecttry {    //jObj = new JsONObject(JsonString);    JsONArray ja = new JsONArray(result);    int size = ja.length();    Log.d("tag", "No of Elements " + ja.length());} catch (JsONException e) {    Log.e("JsON Parser", "Error parsing data " + e.toString());}

任何人都可以帮忙,我的守则不起作用？
我想解析标题,公司名称,类别等…

解决方法:

您需要从Jsonstring创建JsONArray.

您在JsONArray中有JsONArray,然后是JsONObect ..

 try {        JsONArray ja = new JsONArray(buffer.toString());        JsONArray innerjsonArray = ja.getJsonArray(0);        JsONObject object = innerjsonArray.getJsONObject(0);        String Title = object.getString("Title");                     }      catch (JsONException e) {        Log.e("JsON Parser", "Error parsing data " + e.toString());     }

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