[{msg = "Hi This is Jecky";name = Susheel;sender = 77;timestamp = 1464241769520;username = susheel;},{msg = dubai;name = Jecky;sender = 78;timestamp = 1464246547147;username = Jecky;},{msg = "How are you ?";name = Susheel;sender = 77;timestamp = 1464243480381;username = susheel;},{msg = "Aje dekhai nai";name = Jecky;sender = 78;timestamp = 1464244974198;username = Jecky;}]
>我有这样的阵列.我想在swift 2.3或最新版本的swift中使用时间戳对这个数组进行排序.任何人都可以帮助我吗?
解决方法let array=[ [ "msg":"Hi This is Jecky","name":"Susheel","sender":77,"timestamp":1464241769520,"username":"susheel",],[ "msg":"dubai","name":"Jecky","sender":78,"timestamp":1464246547147,"username":"Jecky",[ "msg":"How are you ?","timestamp":1464243480381,[ "msg":"Aje dekhai nai","timestamp":1464244974198,] print("array = \(array)") let sortedArray=array.sort { (obj1,obj2) -> Bool in return (obj1["timestamp"] as! Double) < (obj2["timestamp"] as! Double) } print("sortedArray = \(sortedArray)")总结
以上是内存溢出为你收集整理的ios – 如何按升序排序数组swift 2.3全部内容,希望文章能够帮你解决ios – 如何按升序排序数组swift 2.3所遇到的程序开发问题。
如果觉得内存溢出网站内容还不错,欢迎将内存溢出网站推荐给程序员好友。
欢迎分享,转载请注明来源:内存溢出
评论列表(0条)