<?xml version="1.0" enCoding="UTF-8"?><PrintLetterbarcodeData uID="685860050795" name="Sangeetha D" gender="F" yob="1989" co="W/O: Dhanansekaran" house="632" street="Saradhambal nagar" lm="agaramel" vtc="Nazarathpettai" po="Nazarethpettai" dist="Tiruvallur" subdist="Poonamallee" state="Tamil Nadu" pc="600123" dob="03/06/1989"/>
我尝试使用以下代码进行解析
public func parser(parser: NSXMLParser,dIDStartElement elementname: String,namespaceURI: String?,qualifIEdname qname: String?,attributes attributeDict: [String : String]) { currentElement=elementname; print(currentElement)}public func parser(parser: NSXMLParser,dIDEndElement elementname: String,qualifIEdname qname: String?) { currentElement="";}public func parser(parser: NSXMLParser,foundCharacters string: String) {}
但它总是将currentElement作为“PrintLetterbarcodeData”返回
解决方法 这是我在Swift 3中编写的一些解析代码,基于我之前在Swift 2.0中编写的 Google News RSS reader.我修改了这段代码来处理PrintLetterbarcodeData元素列表以及单个元素:class barcodeData { var uID: String var name: String var gender: String var yob: String var co: String var house: String var street: String var lm: String var vtc: String var po: String var dist: String var subdist: String var state: String var pc: String var dob: String init?(dictionary: [String : String]) { guard let uID = dictionary["uID"],let name = dictionary["name"],let gender = dictionary["gender"],let yob = dictionary["yob"],let co = dictionary["co"],let house = dictionary["house"],let street = dictionary["street"],let lm = dictionary["lm"],let vtc = dictionary["vtc"],let po = dictionary["po"],let dist = dictionary["dist"],let subdist = dictionary["subdist"],let state = dictionary["state"],let pc = dictionary["pc"],let dob = dictionary["dob"] else { return nil } self.uID = uID self.name = name self.gender = gender self.yob = yob self.co = co self.house = house self.street = street self.lm = lm self.vtc = vtc self.po = po self.dist = dist self.subdist = subdist self.state = state self.pc = pc self.dob = dob }}class MyParser: NSObject { var parser: XMLParser var barcodes = [barcodeData]() init(xml: String) { parser = XMLParser(data: xml.data(using: String.EnCoding.utf8)!) super.init() parser.delegate = self } func parseXML() -> [barcodeData] { parser.parse() return barcodes }}extension MyParser: XMLParserDelegate { func parser(_ parser: XMLParser,attributes attributeDict: [String : String]) { if elementname == "PrintLetterbarcodeData" { if let barcode = barcodeData(dictionary: attributeDict) { barcodes.append(barcode) } } }}
用法:
let xmlString = "<?xml version=\"1.0\" enCoding=\"UTF-8\"?><PrintLetterbarcodeData uID=\"685860050795\" name=\"Sangeetha D\" gender=\"F\" yob=\"1989\" co=\"W/O: Dhanansekaran\" house=\"632\" street=\"Saradhambal nagar\" lm=\"agaramel\" vtc=\"Nazarathpettai\" po=\"Nazarethpettai\" dist=\"Tiruvallur\" subdist=\"Poonamallee\" state=\"Tamil Nadu\" pc=\"600123\" dob=\"03/06/1989\"/>"let parser = MyParser(xml: xmlString)let barcodes = parser.parseXML() // array of barcodesbarcodes.first // your barcode总结
以上是内存溢出为你收集整理的iOS swift中的xml解析全部内容,希望文章能够帮你解决iOS swift中的xml解析所遇到的程序开发问题。
如果觉得内存溢出网站内容还不错,欢迎将内存溢出网站推荐给程序员好友。
欢迎分享,转载请注明来源:内存溢出
评论列表(0条)