android – 来自AudioRecord的Amplitude

概述我有一些代码应该从AudioRecord获取振幅.问题是数学只返回-Infinity.我可以再多看一眼与我一起看看吧： private class measureSnoreAudio extends AsyncTask<String, String, String> { @Override protected String doInBackground(String... par 我有一些代码应该从AudioRecord获取振幅.问题是数学只返回-Infinity.我可以再多看一眼与我一起看看吧：

private class measureSnoreAudio extends AsyncTask<String,String,String> {    @OverrIDe    protected String doInBackground(String... params) {            Log.d(TAG,"Creating the buffer of size " + BUFFER_SIZE);            byte[] buffer = new byte[BUFFER_SIZE];            Log.d(TAG,"Creating the AudioRecord");            recorder = new AudioRecord(MediaRecorder.AudioSource.MIC,RECORDING_RATE,CHANNEL,FORMAT,BUFFER_SIZE * 10);            Log.d(TAG,"AudioRecord recording...");            recorder.startRecording();            while (isRecordingSnore) {                // read the data into the buffer                int read = recorder.read(buffer,buffer.length);                int amplitude = (buffer[0] & 0xff) << 8 | buffer[1];                // Determine amplitude                double amplitudeDb = 20 * Math                        .log10(Math.abs(amplitude) / 32768);                String dbString = String.valueOf(amplitudeDb);                Log.d("Snore DB","dB " + dbString);                //TextVIEw textAmplitude = (TextVIEw) findVIEwByID(R.ID.tvAmplitude);                //textAmplitude.setText(dbString);            }            Log.d(TAG,"AudioRecord finished recording");        return null;    }}

解决方法

double amplitudeDb = 20 * Math.log10(Math.abs(amplitude) / 32768);

我想问题可能来自Math.abs(幅度)/ 32768,幅度是整数,所以Math.abs(幅度)也将返回整数,因为Math.abs(幅度)小于32768(也许我不正确,字节最大为2 ^ 7 – 1,这里幅度可以大于32768吗？).所以Math.abs(幅度)/ 32768等于0.Log10(0)是-Infinity,我在Eclipse中用Java项目测试过.
你可以改为

double amplitudeDb = 20 * Math.log10((double)Math.abs(amplitude) / 32768);

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