在Android中使用MVP模式时,应该写哪些Android服务调用和调用GoogleAPIClient？

概述我试图通过参考这个链接： https://github.com/jpotts18/android-mvp在我的Android项目中实现MVP模式 我已经成功实现了视图/演示者/交互者类.我不清楚 >哪里可以把服务电话代码？ Since i cannot get the context inside the presenter or interactor class, I am not able t 我试图通过参考这个链接： https://github.com/jpotts18/android-mvp在我的AndroID项目中实现MVP模式

我已经成功实现了视图/演示者/交互者类.我不清楚

>哪里可以把服务电话代码？

Since i cannot get the context insIDe the presenter or interactor
class,I am not able to put the service call there

>在哪里实现Googleapiclient类？

Since Googleapiclient also requires context to run,it also cannot be
implemented insIDe the presenter or interactor without a context

解决方法 使用匕首可以更容易地在演示者上注入Interactor.尝试此链接( https://github.com/spengilley/AndroidMVPService)

我试图实现它没有匕首.但这似乎违反了MVP架构.

从Activity开始,我创建了一个Interactor实例.然后使用Interactor创建Presenter的实例作为参数之一.

活动

public class SomeActivity extends Activity implements SomeVIEw {   private SomePresenter presenter;   @OverrIDe   protected voID onCreate(Bundle savedInstanceState) {      super.onCreate(savedInstanceState);      SomeInteractor interactor = new SomeInteractorImpl(SomeActivity.this);      presenter = new SomePresenterImpl(interactor,this);   }   @OverrIDe   protected voID onStart() {     super.onStart();     presenter.startServiceFunction();   }

主持人

public interface SomePresenter {   public voID startServiceFunction();}

演示者实现

public class SomePresenterImpl implements SomePresenter {   private SomeInteractor interactor;   private SomeVIEw vIEw;   public SomePresenterImpl(SomeInteractor interactor,SomeVIEw vIEw){      this.interactor = interactor;      this.vIEw = vIEw;   }   @OverrIDe   public voID startServiceFunction() {      interactor.startServiceFunction();   }}

交互器

public interface SomeInteractor {   public voID startServiceFunction();}

互动实现

public class SomeInteractorImpl implements SomeInteractor {   private Context context;   public SomeInteractorImpl(Context context) {      this.context = context;   }   @OverrIDe   public voID startServiceFunction() {      Intent intent = new Intent(context,SomeService.class);      context.startService(intent);   }}

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