在Android中解析嵌套的JSON对象

概述我正在尝试解析一个 JSON对象,其中一部分看起来像这样： {"offer":{ "category":"Salon", "description":"Use this offer now to enjoy this great Salon at a 20% discount. ", "discount":"20", "expiration":"2011-04-0 我正在尝试解析一个 JSON对象,其中一部分看起来像这样：

{"offer":{    "category":"Salon","description":"Use this offer Now to enjoy this great Salon at a 20% discount. ","discount":"20","expiration":"2011-04-08T02:30:00Z","published":"2011-04-07T12:00:33Z","rescinded_at":null,"Title":"20% off at Jun Hair Salon","valID_from":"2011-04-07T12:00:31Z","valID_to":"2011-04-08T02:00:00Z","ID":"JUN_HAIR_1302177631","business":{        "name":"Jun Hair Salon","phone":"2126192989","address":{            "address_1":"12 Mott St","address_2":null,"city":"New York","cross_streets":"Chatham Sq & Worth St","state":"NY","zip":"10013"        }    },

等等….

到目前为止,通过这样做,我能够非常简单地解析：

JsONObject jObject = new JsONObject(content);JsONObject offerObject = jObject.getJsONObject("offer");String attributeID = offerObject.getString("category");System.out.println(attributeID);String attributeValue = offerObject.getString("description");System.out.println(attributeValue);String TitleValue = offerObject.getString("Title");System.out.println(TitleValue);`

但是,当我尝试’名称’时,它将无法正常工作.

我试过了：

JsONObject businessObject = jObject.getJsONObject("business");String nameValue = businesObject.getString("name");System.out.println(nameValue);

当我尝试这个时,我得到“JsONObject [business] not found.”

当我尝试：

String nameValue = offerObject.getString("name");System.out.println(nameValue);`

正如预期的那样,我得到“未找到JsONObject [name]”.

我在这做错了什么？我遗漏了一些基本的东西……

解决方法 好吧,我是个白痴.这很有效.

JsONObject businessObject = offerObject.getJsONObject("business");String nameValue = businessObject.getString("name");System.out.println(nameValue);

如果我只想在张贴前两秒钟……杰斯！

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