按汉语拼音首字母查询数据

方法一：建一个拼音表 t_cosler ，存放每个字母开头的第一个汉字的编号和最后一个汉字的编号。 +------+--------+-------+ | f_PY | cBegin | cEnd | +------+--------+-------+ | A | 45217 | 45252 | | B | 45253 | 45760 | | Z | 54481 | 55289 | +------+--------+-------+ 然后直接查询就行了。

mysql> create table t_cosler( -> f_PY char primary key, -> cBegin SMALLINT UNSIGNED not null, -> cEnd SMALLINT UNSIGNED not null -> ); Query OK, 0 rows affected (009 sec) mysql> insert into t_cosler values -> ('A',0xB0A1,0xB0C4), -> ('B',0xB0C5,0xB2C0), -> ('C',0xB2C1,0xB4ED), -> ('D',0xB4EE,0xB6E9), -> ('E',0xB6EA,0xB7A1), -> ('F',0xB7A2,0xB8C0), -> ('G',0xB8C1,0xB9FD), -> ('H',0xB9FE,0xBBF6), -> ('J',0xBBF7,0xBFA5), -> ('K',0xBFA6,0xC0AB), -> ('L',0xC0AC,0xC2E7), -> ('M',0xC2E8,0xC4C2), -> ('N',0xC4C3,0xC5B5), -> ('O',0xC5B6,0xC5BD), -> ('P',0xC5BE,0xC6D9), -> ('Q',0xC6DA,0xC8BA), -> ('R',0xC8BB,0xC8F5), -> ('S',0xC8F6,0xCBF9), -> ('T',0xCBFA,0xCDD9), -> ('W',0xCDDA,0xCEF3), -> ('X',0xCEF4,0xD188), -> ('Y',0xD1B9,0xD4D0), -> ('Z',0xD4D1,0xD7F9); Query OK, 23 rows affected (016 sec) Records: 23 Duplicates: 0 Warnings: 0 mysql> select from o_personnel; +------+------------+ | A_Id | A_UserName | +------+------------+ | 1 | 首先 | | 2 | 检查 | | 3 | 我们 | | 4 | 的二 | | 5 | 进制 | | 6 | 是否 | | 7 | 适合 | | 8 | 你的 | | 9 | 平台 | +------+------------+ 9 rows in set (000 sec) mysql> select p,c -> from o_personnel p , t_cosler c -> where CONV(HEX(left(A_UserName,1)),16,10) between ccBegin and ccEnd; +------+------------+------+--------+-------+ | A_Id | A_UserName | f_PY | cBegin | cEnd | +------+------------+------+--------+-------+ | 4 | 的二 | D | 46318 | 46825 | | 2 | 检查 | J | 48119 | 49061 | | 5 | 进制 | J | 48119 | 49061 | | 8 | 你的 | N | 50371 | 50613 | | 9 | 平台 | P | 50622 | 50905 | | 1 | 首先 | S | 51446 | 52217 | | 6 | 是否 | S | 51446 | 52217 | | 7 | 适合 | S | 51446 | 52217 | | 3 | 我们 | W | 52698 | 52979 | +------+------------+------+--------+-------+ 9 rows in set (000 sec) mysql> 查Ｓ开头的

mysql> select p -> from o_personnel p , t_cosler c -> where CONV(HEX(left(A_UserName,1)),16,10) between ccBegin and ccEnd -> and cf_PY='S'; +------+------------+ | A_Id | A_UserName | +------+------------+ | 1 | 首先 | | 6 | 是否 | | 7 | 适合 | +------+------------+ 3 rows in set (000 sec) mysql> 方法二：不用这个t_cosler表，直接写个函数权限汉字得到拼音。

局限性：　以上方法，均依照汉字区位表来实现，对区位后面的复杂字，无法准确判断，对多音字无法准确判断。

方法三：从微软拼音中导出所有汉字的拼音表。方法四不建表 mysql> SELECT , -> ELT(INTERVAL(CONV(HEX(left(A_UserName,1)),16,10), -> 0xB0A1,0xB0C5,0xB2C1,0xB4EE,0xB6EA,0xB7A2,0xB8C1,0xB9FE,0xBBF7,0 xBFA6,0xC0AC,0xC2E8,0xC4C3,0xC5B6,0xC5BE,0xC6DA,0xC8BB,0xC8F6,0xCBFA,0xCDDA,0xCE F4,0xD1B9,0xD4D1), -> 'A','B','C','D','E','F','G','H','J','K','L','M','N','O','P','Q', 'R','S','T','W','X','Y','Z') as PY -> from o_personnel; +------+------------+------+ | A_Id | A_UserName | PY | +------+------------+------+ | 1 | 首先 | S | | 2 | 检查 | J | | 3 | 我们 | W | | 4 | 的二 | D | | 5 | 进制 | J | | 6 | 是否 | S | | 7 | 适合 | S | | 8 | 你的 | N | | 9 | 平台 | P | +------+------------+------+ 9 rows in set (000 sec) mysql> 方法五： mysql> SELECT , -> CHAR(INTERVAL(CONV(HEX(left(A_UserName,1)),16,10), -> 0xB0A1,0xB0C5,0xB2C1,0xB4EE,0xB6EA,0xB7A2,0xB8C1,0xB9FE, -> 0xBBF7,0xBBF7,0xBFA6,0xC0AC,0xC2E8,0xC4C3,0xC5B6,0xC5BE, -> 0xC6DA,0xC8BB,0xC8F6,0xCBFA,0xCDDA,0xCDDA,0xCDDA,0xCEF4, -> 0xD1B9,0xD4D1)+64) as PY -> from o_personnel; +------+------------+------+ | A_Id | A_UserName | PY | +------+------------+------+ | 1 | 首先 | S | | 2 | 检查 | J | | 3 | 我们 | W | | 4 | 的二 | D | | 5 | 进制 | J | | 6 | 是否 | S | | 7 | 适合 | S | | 8 | 你的 | N | | 9 | 平台 | P | +------+------------+------+ 9 rows in set (000 sec) mysql>

那是因为设计数据库表时多出2列，一列是全拼，一列是简拼，举个例子，就拿搜歌曲，先看表

py_name py_name_j zw_name

wusuowei wsw 无所谓

这样就容易了

如下代码可打印大写字母表

public class English {

public void printEnglish()

{

int firstEnglish, lastEnglish;

char firstE = 'A', lastE = 'Z'; //获取首字母与末字母的值

firstEnglish = (int)firstE;

lastEnglish = (int)lastE;

Systemoutprintln("英文大写字母表： ");

for(int i = firstEnglish; i <= lastEnglish; ++i)

{

char uppercase, lowercase;

uppercase = (char)i;

lowercase = (char)(i + 32);

Systemoutprint(" " + uppercase + lowercase);

}

Systemoutprintln();

}

}

import javautilScanner;

public class Assignment3 {

  public static void main(String[] args) {

    Systemoutprintln("What are your first, middle, and last names");

    Scanner scan = new Scanner(Systemin);

    String fullName = scannextLine();

    if (fullName == null) {

      promptWrongName();

      return;

    }

    String[] names = fullNamesplit(" ");

    if (!verifyNames(names))

      return;

    printNames(names);

  }

  private static void printNames(String[] names) {

    printInitials(names);

    printVariationOne(names);

    printVariationTwo(names);

  }

  private static String capitalizeFirstLetter(String name) {

    return nametrim()substring(0, 1)toUpperCase() + nametrim()substring(1)toLowerCase();

  }

  private static String getInitialInUpperCase(String name) {

    return nametrim()substring(0, 1)toUpperCase();

  }

  private static void printVariationTwo(String[] names) {

    Systemoutprint("Variation Two: ");

    Systemoutprint(capitalizeFirstLetter(names[nameslength - 1]));

    Systemoutprint(", ");

    Systemoutprint(capitalizeFirstLetter(names[0]));

    if (nameslength == 3) {

      Systemoutprint(" ");

      Systemoutprint(capitalizeFirstLetter(names[1]));

    }

    Systemoutprintln();

  }

  private static void printVariationOne(String[] names) {

    Systemoutprint("Variation One: ");

    Systemoutprint(names[nameslength - 1]trim()toUpperCase());

    Systemoutprint(", ");

    Systemoutprint(capitalizeFirstLetter(names[0]));

    if (nameslength == 3) {

      Systemoutprint(" ");

      Systemoutprint(getInitialInUpperCase(names[1]));

      Systemoutprint("");

    }

    Systemoutprintln();

  }

  private static void printInitials(String[] names) {

    Systemoutprint("Your initials are: ");

    for (int i = 0; i < nameslength; i++) {

      Systemoutprint(getInitialInUpperCase(names[i]));

    }

    Systemoutprintln();

  }

  private static boolean verifyNames(String[] names) {

    if (nameslength != 2 && nameslength != 3) {

      promptWrongName();

      return false;

    }

    for (int i = 0; i < nameslength; i++) {

      if (""equals(names[i]trim())) {

        promptWrongName();

        return false;

      }

    }

    return true;

  }

  private static void promptWrongName() {

    Systemoutprintln("Wrong Please enter your names properly");

  }

}

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