这样就可以了：
<html>
<head>
<title></title>
<script type="text/javascript">
var xml = '<xml version="10" encoding="utf-8"><root><text>fda</text><text>ffff</text><text>r32&f23r</text></root>';
var dom = new ActiveXObject("MSXML2DOMDocument40");
domloadXML(xml);
var nodes = domselectNodes("/root/text");
for (var i = 0; i < nodeslength; i++) {
alert(nodes[i]text);
}
</script>
</head>
<body>
</body>
</html>
注意xml里面的&要换成&不然xml是不正确哈。
我最近也做这个事情，我不限制的服务，然后自动识别，呼叫麻烦了。
点击一个链接，转到jsp页面，运行一个类似的计划，在jsp中显示的结果。
参考： >
可以把我以前做的解析和生成XML的代码给你看一下，你可以参考参考：
代码如下：
public static class PaperXMLManager
{
/// <summary>
/// </summary>
public static void GetExamPaperXMLStr(XmlDocument objXmlDoc, EntityArrayList<Item> items, string paperCode, ExamPolicy examPolicy)
{
XmlNode root = objXmlDocSelectSingleNode("ExamPaper");
XmlNode node;
XmlElement subnode;
if (root == null)
{
root = objXmlDocCreateElement("ExamPaper"); //创建一个<ExamPaper>根节点
objXmlDocAppendChild(root);
}
else
{
root = objXmlDocSelectSingleNode("ExamPaper");//查找<ExamPaper>根节点
}
foreach (Item it in items)
{
node = objXmlDocCreateElement("Item");
subnode = objXmlDocCreateElement("Code");
subnodeInnerText = itCode;
nodeAppendChild(subnode);
subnode = objXmlDocCreateElement("Ver");
subnodeInnerText = itVerToString();
nodeAppendChild(subnode);
subnode = objXmlDocCreateElement("Score");
subnodeInnerText = examPolicyScorePerItemToString();
nodeAppendChild(subnode);
subnode = objXmlDocCreateElement("EPCode");
subnodeInnerText = examPolicyEPCode;
nodeAppendChild(subnode);
rootAppendChild(node);
}
}
/// <summary>
/// 获取Xml格式字符串的内容
/// </summary>
/// <param name="str">Xml格式字符串</param>
/// <returns>Xml内容的DataTable</returns>
public static DataTable GetItemTable(string str)
{
XmlDocument objXmlDoc = GetXmlDocByStr(str);
DataTable dt = new DataTable();
dtColumnsAdd("Code");
dtColumnsAdd("Ver");
dtColumnsAdd("Score");
dtColumnsAdd("EPCode");
XmlNodeList nodes = objXmlDocGetElementsByTagName("Item");
foreach (XmlNode xmlNode in nodes)
{
DataRow dr = dtNewRow();
for (int j = 0; j < xmlNodeChildNodesCount; j++)
{
dr[j] = xmlNodeChildNodes[j]InnerText;
}
dtRowsAdd(dr);
}
return dt;
}
/// <summary>
/// 获取Xml的内容
/// </summary>
/// <param name="objXmlDoc">Xml文件</param>
/// <returns>Xml内容的DataTable</returns>
public static DataTable GetItemTable(XmlDocument objXmlDoc)
{
DataSet ds = new DataSet();
StringReader read = new StringReader(objXmlDocSelectSingleNode("ExamPaper")OuterXml);
dsReadXml(read);
DataTable tblRes = new DataTable();
tblRes = dsTables[0];
return tblRes;
}
/// <summary>
/// 从指定格式的字符串中加载Xml文档
/// </summary>
/// <param name="str">xml格式的字符串</param>
/// <returns>xml文档对象</returns>
public static XmlDocument GetXmlDocByStr(string str)
{
XmlDocument dom = new XmlDocument();
domLoadXml(str);
return dom;
}
/// <summary>
/// 在当前XML中找到指定值的节点
/// </summary>
/// <param name="objXmlDoc">xml</param>
/// <param name="itemCode">节点内容</param>
/// <returns>节点</returns>
public static XmlNode GetNode(XmlDocument objXmlDoc, string itemCode)
{
XmlNode Nodelist = objXmlDocSelectSingleNode("ExamPaper");
foreach (XmlNode node in NodelistSelectNodes("Item"))
{
if (nodeSelectSingleNode("Code")InnerText == itemCode)
{
return node;
}
}
return null;
}
/// <summary>
/// 替换掉XML文件中值为oldItemCode的节点下子节点的值
/// </summary>
/// <param name="objXmlDoc">xml对象</param>
/// <param name="oldItemCode">指定节点的值</param>
/// <param name="code">试题编码</param>
/// <param name="ver">试题版本</param>
/// <param name="score">试题分值</param>
/// <param name="epcode">策略编号</param>
/// <returns>替换后的XML对象</returns>
public static XmlDocument ReplaceItem(XmlDocument objXmlDoc, string oldItemCode, string code, string ver, string score, string epcode)
{
try
{
XmlNode node = GetNode(objXmlDoc, oldItemCode);
nodeSelectSingleNode("Code")InnerText = code;
nodeSelectSingleNode("Ver")InnerText = ver;
nodeSelectSingleNode("Score")InnerText = score;
nodeSelectSingleNode("EPCode")InnerText = epcode;
return objXmlDoc;
}
catch
{
return objXmlDoc;
}
}
/// <summary>
/// 删除选定节点
/// </summary>
/// <param name="nodeText">节点内容</param>
/// <param name="xmlStr">xml字符串</param>
/// <returns>删除后XmlDocument对象</returns>
public static XmlDocument DelNode(string nodeText, string xmlStr)
{
XmlDocument xmlDoc = GetXmlDocByStr(xmlStr);
XmlNode node = GetNode(xmlDoc, nodeText);
if (xmlDoc != null)
{
XmlNode Nodelist = xmlDocSelectSingleNode("ExamPaper");
NodelistRemoveChild(node);
return xmlDoc;
}
return xmlDoc;
}
}
以上的方法多一些~你也可以参考我下面的代码~知道XML节点格式后直接解析为一个DataTable，这样你知道内容了就可以显示了：
代码如下：
/// <summary>
/// 从指定格式的字符串中加载Xml文档
/// </summary>
/// <param name="str">xml格式的字符串</param>
/// <returns>xml文档对象</returns>
public static XmlDocument GetXmlDocByStr(string str)
{
XmlDocument dom = new XmlDocument();
domLoadXml(str);
return dom;
}
/// <summary>
/// 获取Xml的内容
/// </summary>
/// <param name="objXmlDoc">Xml文件</param>
/// <returns>Xml内容的DataTable</returns>
public static DataTable GetItemTable(string str)
{
XmlDocument objXmlDoc = GetXmlDocByStr(str);
DataTable dt = new DataTable();
dtColumnsAdd("Code");
dtColumnsAdd("EpCode");
dtColumnsAdd("Ver");
dtColumnsAdd("Score");
dtColumnsAdd("UserScore");
dtColumnsAdd("RightAnswer");
dtColumnsAdd("UserAnswer");
XmlNodeList nodes = objXmlDocGetElementsByTagName("Item");
foreach (XmlNode xmlNode in nodes)
{
DataRow dr = dtNewRow();
for (int j = 0; j < xmlNodeChildNodesCount; j++)
{
dr[j] = xmlNodeChildNodes[j]InnerText;
}
dtRowsAdd(dr);
}
return dt;
}
}
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