c语言:产生50个两位随机整数,并按五个一行的形式输出

#include "stdlib.h"

#include"stdio.h"

#include"time.h"

void main()

{

int n ,a[50],i,j,t

srand(time (NULL))

for(i=0i<50i++)

{

a[i]=rand()%90+10

for(j=0j<i-1j++)

if (a[i]==a[j])

i--

}

printf("nafter:\n")

for(i=0i<50i++) // 下面这是打印输出

{

if (i%5==0)// 十个数字换行

printf("\n")

printf("%d ",a[i])

}

return 0

}

#include<stdio.h>

#include<math.h>

void main()

{

int x

int i

int f

for(i=1i<=50i++)

{

f=rand()

x=f%(99-10+1)+10

printf(''%d'',x)

if(i%5==0)

printf(''\n'')

}

}

Dim n As Integer, i As Integer, x As Integer

Dim s1 As String, s2 As String

Randomize

For i = 1 To 50

x = Int(Rnd * 50) + 1

s1 = s1 &x

If i Mod 10 = 0 Then

s1 = s1 &vbCrLf

Else

s1 = s1 &" "

End If

If x Mod 6 = 2 Then

n = n + 1

s2 = s2 &x

If n Mod 10 = 0 Then

s2 = s2 &vbCrLf

Else

s2 = s2 &" "

End If

End If

Next

Print "产生的50个随机数如下"

Print s1

Print "其中被6除余2的数有" &n &"个"

Print s2

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