1、有一分段函数如下，请编写程序，输入x值，输出y值。 当x<=-1 y=sinx+2cosx 当-1<x<=1 y=1(x2-1) 当x>1

#include<stdio.h>

#include<cmath>

int main()

{

float x,y

scanf("%f",&x)

if (x<=-1){

y=3*sqrt(-x+2)+1

printf("%.5f",y)}

else if (x>=10){

y=sqrt((x+1)/(2*x*x))

printf("%f",y)}

else{

y=pow(x,5)+1

printf("%.0f",y)}

}

扩展资料

using namespace std

class CStudent

{

public:

char szName[20]

int age

}

int main()

{

CStudent s     

fstream ioFile("students.dat", ios::in|ios::out)//

if(!ioFile) {

cout <<"error"

return 0

  }

#include

int main()

{

int x,y

scanf("%d",&x)

if(0<x&&x<10) y=3*x+2

else

{if(x=0) y=0

else

{if (x<0) y=x*x

else printf("go die\n")

}

}

printf("%d",y)

return 0

}该程序的分段函数如下:

f(x)=3x+2  (0<x<10)

f(x)=1         (x=0)

f(x) = x*x    (x<0)

#include <stdio.h>

#include <math.h>

void main()

{

float x

double y

printf("Please input the value of x:")

scanf("%f",&x)

if(x>=-10&&x<=4)

{

y=fabs(x-2)

printf("y=%.2f\n",y)

}

else if(x>=5&&x<=7)

{

y=x+10

printf("y=%.2f\n",y)

}

else if(x>=8&&x<=12)

{

y=pow(x,4)

printf("y=%.2f\n",y)

}

else

printf("No answer\n")

}

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