请问，用四个独立按键来制作简易密码锁C语言程序该怎么编写

这个可以模拟那种拨码形式的密码锁方式来设计，比如OFO共享单车的拨码方式。

#include<reg51.h>

#define uchar unsigned char

uchar mima[4]={1,2,3,4}

uchar keymm[4]={0,0,0,0}

sbit key1=P1^0

sbit key2=P1^1

sbit key3=P1^2

sbit key4=P1^3

sbit led=P1^4

bit flag=0

void delay(uchar a)

{

uchar i

while(a--)for(i=0i<120i++)

}

main()

{

uchar i

led=1

while(1)

{

if(key1==0)

{

while(key1==0)

keymm[0]++

keymm[0]%=10

}

if(key2==0)

{

while(key2==0)

keymm[1]++

keymm[1]%=10

}

if(key3==0)

{

while(key3==0)

keymm[2]++

keymm[2]%=10

}

if(key4==0)

{

while(key4==0)

keymm[3]++

keymm[3]%=10

}

for(i=0i<4i++)

{

if(keymm[i]!=mima[i])break

if(i==3)flag=1

}

if(flag)

{

i=10

while(i--)

{

led=~led

delay(100)

}

flag=0

}

}

}

sbit KEY = P0^1

sbit LED = P0^2

int keyscan(void)

{

bit keyval=0

if(KEY)

{

delay(30)//延时消抖

if(KEY)

{

keyval = ~keyval//值取反

if(keyval )

{

LED = 1//led亮

}

else

{

LED = 0//led灭

}

}

}

}

#include<reg52.h>

#define uchar unsigned char

#define uint unsigned int

uchar code table[]=

{

0x3f,0x06,0x5b,0x4f,0x66,

0x6d,0x7d,0x07,0x7f,0x6f,

}

sbit key1=P3^4

uchar num=0

void delay(uint z)

void main()

{

while(1)

{

P2=0xfe

P0=table[num]

delay(50)

if(key1==0)

{

while(!key1)

num++

}

if(num==10)

{

num=0

}

}

}

void delay(uint z)

{

while(z--)

}

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