运用51单片机实现4位8段LED数码管的动态数字显示，写出C语言程序

#include<reg52.h>

#define

uchar

unsigned

char

#define

uint

unsigned

int

uchar

count

uint

disnum

sbit

dula=P2^6

sbit

wela=P2^7

uchar

code

tabledu[]={

0x3f,0x06,0x5b,0x4f,

0x66,0x6d,0x7d,0x07,

0x7f,0x6f,0x77,0x7c,

0x39,0x5e,0x79,0x71}

display(uchar,uchar,uchar)

delay(uchar)

void

main()

{

EA=1

ET1=1

TMOD=0x10

TH1=(65536-50000)/256

TL1=(65536-50000)%256

TR1=1

while(1)

{

if(count==20)

{

count=0

//

if(disnum==1000)

//

disnum=0

disnum++

}

display(disnum/100,disnum%100/10,disnum%100%10)

}

}

void

tim1()

interrupt

3

using

3

{

TH1=(65536-50000)/256

TL1=(65536-50000)%256

count++

}

display(uchar

bai,uchar

shi,uchar

ge)

{

P0=tabledu[bai]

dula=1

dula=0

P0=0xfe

wela=1

wela=0

delay(1)

P0=tabledu[shi]

dula=1

dula=0

P0=0xfd

wela=1

wela=0

delay(1)

P0=tabledu[ge]

dula=1

dula=0

P0=0xfb

wela=1

wela=0

delay(1)

}

delay(uchar

x)

{

uchar

a,b

for(a=xa>0a--)

for(b=255b>0b--)

}

//你自己看一下,有不对的就改点.别忘了给分啊

主要程序如下：

uchar table[8]={1,3,5,7,2,4,6,8}//要显示的数字

uchar qiduan_tab[10]={.........}//七段码

while(1)

{

for(i=0i<5i++)//先显示1357，第二次显示3572 第三次显示5724

{

for(j=0j<20j++)//刷新20次约0.4秒，推进一位

{

wei1=0P0= table[qiduan_tab[ i]delayms(5)wei1=1

wei2=0P0= table[qiduan_tab[ i+1]delayms(5)wei2=1

wei3=0P0= table[qiduan_tab[ i+2]delayms(5)wei3=1

wei4=0P0= table[qiduan_tab[ i+3]delayms(5)wei4=1

}

}

}

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