用VB编写双色球程序，要求是以指定数字为尾的数字中随机选择该怎么编写程序

建立两个Command1和2

Dim RedBalls, BullBalls

Private Sub Command1_Click()

'Label1.Caption = ""

rarr = GetRndNotRepeat(0, UBound(RedBalls), 6)

barr = GetRndNotRepeat(0, UBound(BullBalls), 1)

For i = 1 To 6

t = Now

Do

DoEvents

Loop While DateDiff("s", t, Now) <1.5

FillStyle = 0

FillColor = vbRed

Form1.Circle (500 + i * 500, 1000), 200, vbRed

CurrentX = 350 + i * 500

CurrentY = 840

Print Format(RedBalls(rarr(i)), "00")

Next i

t = Now

Do

DoEvents

Loop While DateDiff("s", t, Now) <2

i = 7

FillStyle = 0

FillColor = vbBlue

Form1.Circle (500 + i * 500, 1000), 200, vbBlue

CurrentX = 350 + i * 500

CurrentY = 840

Print Format(BullBalls(barr(1)), "00")

End Sub

Private Sub Command2_Click()

End

End Sub

Private Sub Form_Load()

RedBalls = Array(2, 3, 4, 7, 8, 9, 12, 13, 14, 17, 18, 19, 22, 23, 24, 27, 28, 29, 32, 33)

BullBalls = Array(3, 4, 5, 9, 13, 14, 15)

'Label1.Caption = ""

Command1.Caption = "开始"

Command2.Caption = "退出"

Form1.FontSize = 15

Form1.FontName = "Arial"

Form1.ForeColor = &HFFFFFF

End Sub

Public Function GetRndNotRepeat(ByVal NumMin As Integer, ByVal NumMax As Integer, ByVal n As Integer)

Dim arr() As Integer

If n >NumMax - NumMin + 1 Then

ReDim arr(0)

arr(0) = 0

Else

ReDim arr(n)

Dim b() As Byte

Dim m As Integer

m = Int((NumMax - NumMin) / 8)

ReDim b(m)

Dim x As Integer, y As Integer

Dim z As Byte

Randomize

arr(0) = 1

For i = 1 To n

Do

x = Int(Rnd * (NumMax - NumMin + 1)) + NumMin

y = x - NumMin

z = 2 ^ (y Mod 8)

y = y \ 8

Loop While b(y) And z

b(y) = b(y) Or z

arr(i) = x

Next i

End If

GetRndNotRepeat = arr

End Function

已经运行过。

public class RandomDemo {

public static void main(String[] args) {

LotteryTicket lt = new LotteryTicket()

int red[] = lt.getRed()

System.out.print("随机生成的红球为：")

for(int i=0i<6i++){

System.out.print(" "+red[i])

}

System.out.print("\t蓝球为："+lt.getBlue())

}

}

class LotteryTicket{彩票生成类

private int[] red = new int[6]

public int[] getRed(){//返回红球

int i =0

for(i<6i++){

red[i] = (int)(Math.random()*33) +1

for(int j=0j<ij++){//保证了重复，我个从认为这个彩票好像不能重复吧

if(red[i]==red[j]){

red[i] = (int)(Math.random()*33) +1

j=0

}

}

}

return red

}

public int getBlue(){//返回蓝球

return (int)(Math.random()*16) +1

}

}

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