#include
#include
#include
using
namespace
std
int
IsLeapYear(int
year)
{
if(year%4==0)
{
if(year%100==0&&year%400==0)
return
1
else
return
0
}
else
return
0
}
int
getlast_day(int
month,
int
year)
{
switch
(month)
{
case
1:
case
3:
case
5:
case
7:
case
8:
case
10:
case
12:
return
31
break
case
2:
if(
IsLeapYear(year))
return
29
else
return
28
break
default:
return
30
break
}
}
int
check_day(int
last_day,
int
day)
{
if(day>last_day||day<=0)//invalid
return
0
else
return
1
}
void
next_day(int
year,
int
month,
int
day)
{
if(day+1<=getlast_day(month,year))
printf("Next
Day:
%d/%d/%d
",year,month,day+1)
else
{
if(month+1<=12)
printf("Next
Day:
%d/%d/%d
",year,month+1,1)
else
printf("Next
Day:
%d/%d/%d
",year+1,1,1)
}
}
void
main()
{
int
year,month,day
char
flag
do
{
printf("Input
Year\n")
scanf("%d",&year)
printf("Input
Month\n")
scanf("%d",&month)
printf("Input
Day\n")
scanf("%d",&day)
if(!check_day(getlast_day(month,
year),
day))
{
printf("Day
Input
Error.
Input
Please[1
-
31]
integerInput
Day\n")
scanf("%d",&day)
}
else
{
next_day(year,
month,
day)
printf("要终止程序吗?(Y/N)
\n")
scanf("%c",&flag)
if(flag=='Y'||flag=='y')
break
}
}
while(1)
system("pause")
}
#include"stdio.h"
int
isleapyear(int
year)//判断是不是闰年。
int
iscurrentdate(int
year,int
month,int
int
returnnextday(int
year,int
month,int
day)//返回下一天，也有判断是不是正确的日期。
int
leapyear_month_sumday[12]={31,29,31,30,31,30,31,31,30,31,30,31}//闰年数组，保存各月天数。
void
main()
{
int
year=0,month=0,day=0,nextday=0
printf("pleace
enter
right
date(example:2005
6
27):\n")
scanf("%d%d%d",&year,&month,&day)
nextday=returnnextday(year,month,day)
switch
(nextday)
{
case
0:
printf("not
a
current
date\n")
break
case
1:
if
(month==12)
{
year++
month=1
}
else
{
month++
}
break
}
if
(nextday!=0)
printf("the
you
input
next
date
is
%d-%d-%d.thank
use
bye
bye!\n",year,month,nextday)
}
int
isleapyear(int
year)
{
if
(year%4==0)
{
if
(year%400)
return
1
else
{
if
(year%100==0)
return
0
else
return
1
}
}
else
{
return
0
}
}
int
iscurrentdate(int
year,int
month,int
day)
{
if
((year<0)
&&
(year>9999)
&&
(month>12)
&&
(month<1)
&&
(day<1)
&&(day>31)
)return
0
else
return
1
}
int
returnnextday(int
year,int
month,int
day)
{
int
thismonthsumday
if
(iscurrentdate(year,month,day)==1)
{
thismonthsumday=leapyear_month_sumday[month-1]
if
(month==2)
{
if
(isleapyear(year)==0)
thismonthsumday--
}
if
(day<thismonthsumday)
{
return
++day
}
else
{
if
(day==thismonthsumday)
{
return
1
}
else
{
return
0
}
}
}
else
{
return
0
}
}
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