C语言问题: 给出字符点阵，显示字符,请问应如何写程序代码?

分类: 电脑/网络 >>程序设计 >>其他编程语言

问题描述:

这是给出的相关的材料,请教达人指点啊

我不知道如何动手,也不清楚代码要怎么写

希望高手给编写出来吧.谢谢了

/* Chars are defined as 5 columns with each 8 bit, (5x8 font)

lowest 4 dots up to down 1,2,4,8 is higher nibble,

upper 4 dots up to down is lower nibble, for example:

| 123456

-+----------

|

1| xxx 1

2| x x 2

3| x x 4

4| x x __8 "A" is {0x7E,0x11,0x11,0x11,0x7E,0x00} (Last column blank)

5| xxxxx 1

6| x x 2

7| x x 4

8| 8

*/

const byte prime_char_map[][6] = { {0x00,0x00,0x00,0x00,0x00,0x00}, \

/* Block for test at startup */ {0xFF,0xFF,0xFF,0xFF,0xFF,0x00}, \

/* 02 */ {0x00,0x00,0x00,0x00,0x00,0x00}, \

/* 03 */ {0x00,0x00,0x00,0x00,0x00,0x00}, \

/* 04 */ {0x00,0x00,0x00,0x00,0x00,0x00}, \

/* 05 */ {0x00,0x00,0x00,0x00,0x00,0x00}, \

/* 06 */ {0x00,0x00,0x00,0x00,0x00,0x00}, \

/* 07 */ {0x00,0x00,0x00,0x00,0x00,0x00}, \

/* 08 */ {0x00,0x00,0x00,0x00,0x00,0x00}, \

/* 09 */ {0x00,0x00,0x00,0x00,0x00,0x00}, \

/* 0A */ {0x00,0x00,0x00,0x00,0x00,0x00}, \

/* 0B */ {0x00,0x00,0x00,0x00,0x00,0x00}, \

/* 0C */ {0x00,0x00,0x00,0x00,0x00,0x00}, \

/* 0D */ {0x00,0x00,0x00,0x00,0x00,0x00}, \

/* 0E */ {0x00,0x00,0x00,0x00,0x00,0x00}, \

/* 0F */ {0x00,0x00,0x00,0x00,0x00,0x00}, \

/* 10 */ {0x00,0x7F,0x3E,0x1C,0x08,0x00}, \

/* 11 */ {0x08,0x1C,0x3E,0x7F,0x00,0x00}, \

/* 12 */ {0x44,0x66,0x77,0x66,0x44,0x00}, \

/* 13 */ {0x11,0x33,0x77,0x33,0x11,0x00}, \

/* 14 */ {0x48,0x77,0x49,0x41,0x42,0x00}, \

/* 15 */ {0x30,0x48,0x45,0x40,0x20,0x00}, \

/* 16 */ {0x00,0x00,0x7D,0x00,0x00,0x00}, \

/* 17 */ {0x40,0xE0,0xE0,0x7F,0x06,0x00}, \

/* 18 */ {0x24,0x42,0x81,0x42,0x24,0x00}, \

/* 19 */ {0x0F,0xF0,0x00,0xF0,0x0F,0x00}, \

/* 1A */ {0x20,0x40,0x20,0x10,0x08,0x00}, \

/* 1B */ {0x7C,0x82,0x82,0x83,0x44,0x00}, \

/* 1C */

解析:

你的材料不全吧，看样子应该是prime_char_map[][6]第一维应该有256个元素的，你给出来的只是前面的一小部分，这里面很多都不是可显示的字符。下面是根据你的材料写的显示字符的程序：#include <stdio.h>const byte prime_char_map[][6] = {{0x00,0x00,0x00,0x00,0x00,0x00}}这个地方你得把你的材料里的prime_char_map定义全都粘进来void Display(char c)void main(){Display('A')Display('b')}void Display(char c){int i, jbyte bit = 0x01for (i = 0i <8i++){for (j = 0j <6j++){if (prime_char_map[c][j] &bit)printf("x")elseprintf(" ")}printf("\n")bit *= 2}}

常用的点阵规格为8*8或16*16等，9*9点阵显示比较麻烦。

9*9点阵组成的字符A可显示在16*16点阵上，当然用点阵型液晶屏也可显示9*9点阵组成的字符。方法，先取模，字模按9行*16列取，占用9*2=18个字节。编号0 1........17，其中1 3 5 7..........17这9个字节中只有1位有效。因此写程序时，0 2 4等双数字节可显示8个点，1 3 5 7等单数字节只显示1个点。 程序就比较简单 ，对每个字节逐位判断是0还是1，是1画点，是0不显示。

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