c语言设计 分段函数

#include <math.h>

int main()

{

double x,y

scanf("%lf",&x)

if (x<0)

y=0.5*(-x)

else

if (x<10)

y=exp(x)+3

else

if(x<20)

y=log10(x)

else

if (x<30)

y=pow(x,1.5)

else

if (x<50)

y=pow (x,0.5)-1

else

y=3*cos(x)

printf("y=%lf\n",y)

return 0

}

扩展资料

return 0代表程序正常退出。return是C++预定义的语句，它提供了终止函数执行的一种方式。当return语句提供了一个值时，这个值就成为函数的返回值。

return语句用来结束循环，或返回一个函数的值。

1、return 0，说明程序正常退出，返回到主程序继续往下执行。

2、return 1，说明程序异常退出，返回主调函数来处理，继续往下执行。return 0或return 1对程序执行的顺序没有影响，只是大家习惯于使用return(0)退出子程序而已。

#include

int main()

{

int x,y

scanf("%d",&x)

if(0<x&&x<10) y=3*x+2

else

{if(x=0) y=0

else

{if (x<0) y=x*x

else printf("go die\n")

}

}

printf("%d",y)

return 0

}该程序的分段函数如下:

f(x)=3x+2  (0<x<10)

f(x)=1         (x=0)

f(x) = x*x    (x<0)

#include <stdio.h>

#include <math.h>

void main()

{

float x

double y

printf("Please input the value of x:")

scanf("%f",&x)

if(x>=-10&&x<=4)

{

y=fabs(x-2)

printf("y=%.2f\n",y)

}

else if(x>=5&&x<=7)

{

y=x+10

printf("y=%.2f\n",y)

}

else if(x>=8&&x<=12)

{

y=pow(x,4)

printf("y=%.2f\n",y)

}

else

printf("No answer\n")

}

进行数值分段主要进行字符串分割，使用strtok函数即可实现字符串分割。这里引用一段strtok用法：

The strtok() function returns a pointer to the next "token" in str1, where str2 contains the delimiters that determine the token. strtok() returns NULL if no token is found. In order to convert a string to tokens, the first call to strtok() should have str1 point to the string to be tokenized. All calls after this should have str1 be NULL.

For example:char str[] = "now # is the time for all # good men to come to the # aid of their country"

char delims[] = "#"

char *result = NULL

result = strtok( str, delims )

while( result != NULL ) {undefined

printf( "result is \"%s\"\n", result )

result = strtok( NULL, delims )

}

/* 何问起 hovertree.com */

The above code will display the following output:

result is "now "

result is " is the time for all "

result is " good men to come to the "

result is " aid of their country"

---