请高手帮忙写一个对数据库 *** 作的java小程序!求源码!

请高手帮忙写一个对数据库 *** 作的java小程序!求源码!,第1张

public class Mdbda {

Statement stat

Connection con = null

//private String strConnect ="jdbc:odbc:DRIVER=Microsoft Access Driver (*.mdb, *.accdb)DBQ=E:\\sql\\ffxx.accdb"

//类

public Mdbda() {

try {

Class.forName("sun.jdbc.odbc.JdbcOdbcDriver")

String url = "jdbc:odbc:driver=Microsoft Access Driver (*.mdb, *.accdb)DBQ=E://sql//jxjyExam.accdb"

con = DriverManager.getConnection(url)

stat = con.createStatement()

} catch (ClassNotFoundException ex) {

System.out.println("加载驱动失败")

} catch (SQLException ex) {

Logger.getLogger(Mdbda.class.getName()).log(Level.SEVERE, null, ex)

}

}

public List getOtherDa(String where) {

List list = new ArrayList()

try {

String action = "select * from exam " + where

ResultSet rs = null

rs = stat.executeQuery(action)

while (rs.next()) {

String content=rs.getString("content")

list.add(content)

// System.out.println(content)

}

rs.close()

stat.close()

con.close()

} catch (SQLException ex) {

Logger.getLogger(Mdbda.class.getName()).log(Level.SEVERE, null, ex)

}

return list

}

}

其他类中直接调用 new Mdbda().getOtherDa()就可以获取。

以上是access

#include <stdio.h>

void Stat( double a[], int iArrLen)

void main()

{

double a[10]

char ch

int i = 0

printf( "请输入10名学员成绩:\n")

//输入十名学生成绩

for ( i =0i <10i++ )

{

scanf( "%lf", &a[i])

}

Stat( a, 10)

printf( "Press any key to exit...")

scanf( "%c", &ch)

}

void Stat( double a[] , int iArrLen )

{

if ( iArrLen <=0 )

{

return

}

double dAvgScore = 0, dTotalScore = 0//声明平均成绩dAvgScore 和总成绩变量dTotalScore

double dMaxScore = 0, dMinScore = 100//声明最高成绩dMaxScore 和最低成绩变量 dMinScore

int cExcellent = 0, cGood = 0, cPass= 0, cFail = 0 //声明

int i = 0

for ( i=0i <iArrLeni++ )

{

dTotalScore += a[i]//计算总成绩

if ( a[i] >dMaxScore )

{

dMaxScore =a[i]

}

if ( a[i] <dMinScore )

{

dMinScore = a[i]

}

if ( a[i] >84 )

{

++cExcellent

}

else

{

if ( a[i] >= 70 &&a[i] <= 84 )

{

++cGood

}

else

{

if ( a[i] >= 60 )

{

++cPass

}

}

}

}

cFail = iArrLen - cExcellent - cGood - cPass//不及格人数为总人数减去其它人数之和

dAvgScore = dTotalScore / iArrLen//计算平均成绩

printf( " 总成绩: %6.2f\n", dTotalScore )

printf( "平均成绩: %6.2f\n", dAvgScore )

printf( " 最高分: %6.2f\n", dMaxScore )

printf( " 最低分: %6.2f\n", dMinScore )

printf( "\n\n")

printf( "84分以上的: %d名学员\n", cExcellent )

printf( " 70-84分的: %d名学员\n", cGood )

printf( " 60-69分的: %d名学员\n", cPass )

printf( "60分以下的: %d名学员\n", cFail )

}


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原文地址: http://outofmemory.cn/yw/11807860.html

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