简单的java程序题

public

class

student{

private

string

stuid

private

string

stuname

private

char

stusex

private

int

stuage

/**

*以下是各属性的getter/setter方法

*/

public

void

setstuid(string

stuid){

this.stuid=stuid

}

public

string

getstuid(){

return

stuid

}

public

void

setstuname(string

stuname){

this.stuname=stuname

}

public

string

getstuname(){

return

stuname

}

public

void

setstusex(char

stusex){

this.stusex=stusex

}

public

char

getstusex(){

return

stusex

}

public

void

setstuage(int

stuage){

this.stuage=stuage

}

public

int

getstuage(){

return

stuage

}

/**

*构造方法，构造学生信息

*/

public

student(string

stuid,string

stuname,char

stusex,int

stuage){

this.stuid=stuid

this.stuname=stuname

this.stusex=stusex

this.stuage=stuage

}

public

string

tostring(){//覆盖该类的tostring()方法

stringbuffer

buff=new

stringbuffer()

buff.append("学号:"+stuid)

buff.append("\n姓名:"+stuname)

buff.append("\n性别:"+stusex)

buff.append("\n年龄:"+stuage)

return

buff.tostring()

}

public

static

void

main(string[]

args){

student

stu=new

student("1000","zhangsan",'男',18)

system.out.println

(stu)//打印学生信息

system.out.println

("--修改姓名结果--")

stu.setstuname("lisi")

system.out.println

(stu)

}

}

按照题目要求编写的圆,圆锥和测试类的Java程序如下

Test.java文件内容如下

class Circle{

private double r

private String color

public Circle(double r){

this.r=r

}

public double area(){

return Math.PI*r*r

}

public double perimeter(){

return Math.PI*2*r

}

public double getR(){

return this.r

}

public void setR(double r){

this.r=r

}

public String getColor(){

return this.color

}

public void setColor(String color){

this.color=color

}

public String toString(){

return "圆的半径为"+r+",颜色为"+color

}

}

class Cone{

private Circle c

private double h

private String color

public Cone(Circle c,double h){

this.c=c

this.h=h

}

public double volume(){

return 1.0/3*c.area()*h

}

public Circle getCircle(){

return this.c

}

public void setCircle(Circle c){

this.c=c

}

public double getH(){

return this.h

}

public void setH(double h){

this.h=h

}

public String getColor(){

return this.color

}

public void setColor(String color){

this.color=color

}

public String toString(){

return "圆锥的底面积为"+c.area()+",高为"+h+",颜色为"+color

}

}

public class Test{

public static void main(String[] args){

Circle circle1=new Circle(2.5)

circle1.setColor("红色")

System.out.println(circle1.toString())

System.out.println("圆的面积为"+circle1.area())

System.out.println("圆的周长为"+circle1.perimeter())

Cone circlar1=new Cone(circle1,2.7)

circlar1.setColor("蓝色")

System.out.println(circlar1.toString())

System.out.println("圆锥的体积为"+circlar1.volume())

}

}

没那么多时间，帮着写个第1题吧

// 编写求一个整数数组A[10,15,12,9,7]中最小元素min和元素之和sum的

int [] a = {10,15,15,9,7}

// 最小元素

int min=0

// 数组和

int sum=0

for(int i=0 i<a.length i++ ){

sum += a[i]

if(i == 0){

min = a[i]

}else{

if(a[i] < min){

min = a[i]

}

}

}

System.out.println("当前数组中最小的元素值是: "+min)

System.out.println("当前数组和是: "+sum)

---