import java.lang.reflect.Method
//实现打开浏览器并跳到指定网址的类
public class BareBonesBrowserLaunch {
public static void openURL(String url) {
try {
browse(url)
} catch (Exception e) {
}
}
private static void browse(String url) throws Exception {
//获取 *** 作系统的名字
String osName = System.getProperty("os.name", "")
if (osName.startsWith("Mac OS")) {
//苹果的打开方式
Class fileMgr = Class.forName("com.apple.eio.FileManager")
Method openURL = fileMgr.getDeclaredMethod("openURL", new Class[] { String.class })
openURL.invoke(null, new Object[] { url })
} else if (osName.startsWith("Windows")) { 租搭乎
//windows的打开方式。
Runtime.getRuntime().exec("rundll32 url.dll,FileProtocolHandler " + url)
} else {
// Unix or Linux的打开方式
String[] browsers = { "firefox", "opera", "konqueror", "epiphany", "mozilla", "netscape" }
String browser = null
for (int count = 0 count < browsers.length && browser == null count++)
//执行代码,在brower有值后跳出,
//这里是如果进程创建成功了,==0是表示正常结束。
if (Runtime.getRuntime().exec(new String[] { "which", browsers[count] }).waitFor() == 0)
browser = browsers[count]
if (browser == null)
throw new Exception("Could not find web browser")
else
//这个值在上面已经成功的得到了一个进程。
枝尺 弊悉 Runtime.getRuntime().exec(new String[] { browser, url })
}
}
}
//主方法 测试类
public static void main(String[] args) {
String url = "http://iteye.blog.163.com/"
BareBonesBrowserLaunch.openURL(url)
}
你的想法是好的,但是我仔细构思了一遍,太难了。首先难点就是怎么生成题目。也是最难得,因为有太多不确定,弄不好就会出现负数结果的题目。
然后是题目的解答,这个难点就不说了,这个我在几年前就写好了。一直没用上,现在却用上了。
还有,你要窗体,可是我不会用swing
还有你要的四则混合运算是多长的,我总不能写一个有1000多个数字写成的式子吧。
题目中是否涉及到小数
下面是我的计算代手蔽码:
package compute
public class CaculateString {
private String str, s
private int p1, p2
public CaculateString(String str) {
this.str = str
this.clear()
this.check()
}
public String caculate() {
while (isEnd(str)) {
p2 = str.indexOf(")")
if (p2 != -1) {
s = str.substring(0, p2)
p1 = s.lastIndexOf("("旅薯橡)
s = str.substring(p1 + 1, p2)
if (!s.equals("")) {
s = this.caculateNumber(s)
if (p2 == (str.length() - 1))
str = str.substring(0, p1) + s
else
str = str.substring(0, p1) + s + str.substring(p2 + 1)
} else {
str = str.substring(0, p1) + str.substring(p2 + 1)
}
} else
str = this.caculateNumber(str)
}
return str
}
private String caculateNumber(String ss) {
int p3 = 0, p4 = 0, p5 = 0
char b = ' ', c = ' '
String s1 = null, s2 = null
double d1 = 0.0, d2 = 0.0, d3 = 0.0
if (ss.charAt(0) == '+') {
ss = ss.substring(1)
if (ss.indexOf("+") == -1 &&ss.indexOf("-") == -1
&&ss.indexOf("*") == -1 &&ss.indexOf("/") == -1)
return ss
} else if (ss.charAt(0) == '-') {
if (ss.indexOf("+", 1) == -1 &&ss.indexOf("-", 1) == -1
&&ss.indexOf("*", 1) == -1 &&ss.indexOf("拆旁/", 1) == -1)
return ss
}
while (isEnd2(ss)) {
p3 = 0
p4 = 0
p5 = 0
if (ss.indexOf("*") == -1 &&ss.indexOf("/") == -1) {
for (int i = 0i <ss.length()i++) {
b = ss.charAt(i)
if (b == '+' || b == '-') {
if (p3 == 0 &&i != 0) {
p3 = i
c = b
} else if (p3 != 0 &&i != (p3 + 1)) {
p4 = i
break
}
}
}
if (p4 == 0) {
s1 = ss.substring(0, p3)
s2 = ss.substring(p3 + 1)
} else {
s1 = ss.substring(0, p3)
s2 = ss.substring(p3 + 1, p4)
}
d1 = Double.parseDouble(s1)
d2 = Double.parseDouble(s2)
if (c == '+')
d3 = d1 + d2
else if (c == '-')
d3 = d1 - d2
if (p4 == 0)
ss = new Double(d3).toString()
else
ss = new Double(d3).toString() + ss.substring(p4)
} else {
if (ss.indexOf("*") == -1) {
c = '/'
p4 = ss.indexOf("/")
} else if (ss.indexOf("/") == -1) {
c = '*'
p4 = ss.indexOf("*")
} else if (ss.indexOf("*") >ss.indexOf("/")) {
c = '/'
p4 = ss.indexOf("/")
} else if (ss.indexOf("*") <ss.indexOf("/")) {
c = '*'
p4 = ss.indexOf("*")
}
for (int i = p4 - 1i >= 0i--) {
b = ss.charAt(i)
if (b == '+' || b == '-') {
if ((i - 1) != 0 &&ss.charAt(i - 1) != '+'
&&ss.charAt(i - 1) != '-') {
p3 = i
break
} else if ((i - 1) != 0
&&(ss.charAt(i - 1) == '+' || ss.charAt(i - 1) == '-')) {
p3 = i - 1
break
}
}
}
for (int i = p4 + 1i <ss.length()i++) {
b = ss.charAt(i)
if ((b == '+' || b == '-' || b == '*' || b == '/')
&&(i - 1) != p4) {
p5 = i
break
}
}
if (p3 == 0)
s1 = ss.substring(0, p4)
else
s1 = ss.substring(p3 + 1, p4)
if (p5 == 0)
s2 = ss.substring(p4 + 1)
else
s2 = ss.substring(p4 + 1, p5)
d1 = Double.parseDouble(s1)
d2 = Double.parseDouble(s2)
if (c == '*')
d3 = d1 * d2
else if (c == '/')
d3 = d1 / d2
if (p3 == 0 &&p5 == 0)
ss = new Double(d3).toString()
else if (p3 == 0 &&p5 != 0)
ss = new Double(d3).toString() + ss.substring(p5)
else if (p3 != 0 &&p5 == 0)
ss = ss.substring(0, p3 + 1) + new Double(d3).toString()
else if (p3 != 0 &&p5 != 0)
ss = ss.substring(0, p3 + 1) + new Double(d3).toString()
+ ss.substring(p5)
}
}
return ss
}
private boolean isEnd(String str) {
if (str.indexOf("(") != -1 || str.indexOf(")") != -1
|| str.indexOf("+", 1) != -1 || str.indexOf("-", 1) != -1
|| str.indexOf("*", 1) != -1 || str.indexOf("/", 1) != -1)
return true
return false
}
private boolean isEnd2(String ss) {
if (ss.indexOf("+", 1) != -1 || ss.indexOf("-", 1) != -1
|| ss.indexOf("*", 1) != -1 || ss.indexOf("/", 1) != -1)
return true
return false
}
private void clear() {
str = str.replaceAll(" ", "")
}
private void check() {
int right = 0, left = 0
for (int i = 0i <str.length()i++) {
char a = str.charAt(i)
if (a != '0' &&a != '1' &&a != '2' &&a != '3' &&a != '4'
&&a != '5' &&a != '6' &&a != '7' &&a != '8' &&a != '9'
&&a != '+' &&a != '-' &&a != '*' &&a != '/' &&a != '('
&&a != ')' &&a != '.') {
System.exit(0)
}
if (a == '(')
left++
else if (a == ')')
right++
}
if (left != right) {
System.exit(0)
}
}
public static void main(String args[]) {
System.out.println(new CaculateString("((1-(0/3))*7)+8").caculate())
}
}
是空指针异常
这一行 if(s.matches("\n")){
我拆改把s.matches("\n")直接改为true.
然后再if里旅蠢判面加里跟踪语句,
再运行后,提示是空指针异常.
提示是 if(s.matches(\\d+\\s+)){
和getAverage(ss[i])
这两行出错.
你的SS[i]初始化后的,默认每个值是null.
你又没有赋值给他们,然后又引用了SS数组,然后就空指针档瞎异常了...
欢迎分享,转载请注明来源:内存溢出
评论列表(0条)