% Function: Determine the position of the element in array B corresponding to the equivalent element in array A
% Author:Gong Pf. Time:2019-7-2
% Remark: Only consider A and B is one or two dimension
% And x is a size(B,1)*size(B,2) cell
% Each cell x{i,j} is a t*2 array
% (t is the number of times that the element B(i,j) appears in A)
% And x{i,j}(n,1),x{i,j}(n,2) represent the row and column of the element in A
% Example1:A = [1 2 3 4 1 2 8]
% B = [0 1 2]
% x = argmax_min(A,B)
% x = [][2x2 double][2x2 double] = [] [1 11 5] [1 21 6]
% Example2:A = [1 2 42 4 25 9 83 9 3]
% B = [1 32 9]
% x = argmax_min(A,B)
% x = [1x2 double][2x2 double]= [1 1][4 14 3]
% [3x2 double][2x2 double] [1 22 12 3] [3 24 2]
% Interpret the result: (x{1,1}(1,1),x{1,1}(1,2))=(1,1)
%This is where B(1,1) appears in A
% (x{1,2}(1,1),x{1,2}(1,2))=(4,1) and (x{1,2}(2,1),x{1,2}(2,2))=(4,3)
% These are where B(1,2) appears in A
% Can be used to implement argmin and argmax functions
%% A and B array is less or equal two-dimensional
row_col = size(A)
ii = 1
jj = 1
% Count the number of occurrences of elements in one-dimensional array B in A
B_times = zeros(size(B))
for i = 1:size(B,1)
for j = 1:size(B,2)
B_times(i,j) = length(find(A == B(i,j)))
end
end
% Count the position of the element in B in A
for i = 1:size(B,1)
for j = 1:size(B,2)
for m = 1:row_col(1)
for n = 1:row_col(2)
if A(m,n) == B(i,j)
x{i,j}(1,ii) = m
x{i,j}(2,jj) = n
ii = ii + 1
jj = jj + 1
end
end
end
ii = 1
jj = 1
end
end
x=norm(y-ah,2)
x1=min(min(x))
x2=Corresponding_index(x,x1)
disp(x2)
y=λ*norm(h,1)
argmax是一种对函数求参数(集合)的函数。下面是关于argmax函数的简要介绍,大家可以参考一下。
arg函数是什么
当我们有另一个函数y=f(x)时,若有结果x0= argmax(f(x)),则表示当函数f(x)取x=x0的时候,得到f(x)取值范围的最大值。
若有多个点使得f(x)取得相同的最大值,那么argmax(f(x))的结果就是一个点集。
换句话说,argmax(f(x))是使得 f(x)取得最大值所对应的变量点x(或x的集埋告合)。arg即argument,此处意为“自变量”。
max 和 argmax的区别1、y = f(t) 是一般常见的函数式,如果给定一个t值,f(t)函数式会赋一个值给y。
2、y = max f(t) 代表:y 是f(t)函式所有的值中最大的output。
3、y = argmax f(t) 代表:y 是f(t)函式中,会产生最大output的那个参数源液肆t。
例如:假设有雹轿一个函式 f(t),t 的可能范围是 {0,1,2},f(t=0) = 10 f(t=1) = 20 f(t=2) = 7,那分别对应的y如下:y = max f(t) = 20;y= argmax f(t) = 1。
argmax() 函数详解慧庆
[[ 0, 1, 2, 3],
[ 4, 5, 6, 7],
[ 8, 9, 10, 11]] 中[ 8, 9, 10, 11]是槐行最大的铅碧哗
[ 0, 1, 2, 3]中[3]是最大的
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