windows程序如何实现五子棋移动功能

windows程序实现五子棋移动功能步骤如下：

1、通过C+语言来实现一个烂拦猛以windows控制台为展示平台的简单版五子棋程序，通过键盘输入来控制游戏中的行为光标移动，落子，确认。

2、规则要求衡岁某一方在横竖斜方向连续存在五个或五个以上本人所执棋子获得为获胜，要扒一个已存在的程序时，五子棋的程序，可以在互联网里找到很多。

3、可以使用两个int类型的值来表示，白子-1，黑子-2。

4、光标再次移动会改变已记录的落子信息，为了使光标与棋子饥桥不冲突，使用两个图层，表示两个相同的棋盘。

#include <cstdlib>

#include <iostream>

using namespace std

void diaohuan(char shuzhu[],int geshu )

int main(int argc, char *argv[])

{

int geshu,yd

cout<<"请输入棋子(一种)的个数(4的倍数)):"<<endl

cin>>geshu

char shuzhu[100]

int in=0,in1=geshu

for(int n=1n<=geshun++)

{

cout<<" 0 "

shuzhu[in]='0'

in++

}

for(n=1n<=geshun++)

{

cout<<" * "

shuzhu[in1]='*'

in1++

}

for( n=geshu*2n<=geshu*2+2n++)

shuzhu[n]='-'

cout<<"\n你想下棋吗?if you want to play chess,请输入0"<猛慎逗<endl

cin>>yd

if(yd!=0)

{

cout<<"不会下就别捣乱!!"<<endl

system("PAUSE")

return EXIT_SUCCESS

}

else

{

cout<<"欢迎来梦幻棋门!"<<孝局endl

cout<<"loding~~~"枝卖<<endl

cout<<"棋阵为:"<<endl

for(int n=0n<geshu*2+2n++)

cout<<" "<<shuzhu[n]

diaohuan(shuzhu,geshu)

cout<<"最后结果为:"<<endl

for(n=0n<geshu*2+2n++)

cout<<" "<<shuzhu[n]

cout<<endl

system("PAUSE")

return EXIT_SUCCESS

}

}

void diaohuan(char shuzhu[],int geshu )

{

int x=0,y=0,z=4

while(y==0)

{

swap(shuzhu[z-1],shuzhu[z*2])

swap(shuzhu[z],shuzhu[z*2+1])

cout<<endl

for(int n=0n<geshu*2+2n++)

cout<<" "<<shuzhu[n]

z--

swap(shuzhu[z],shuzhu[z*2])

swap(shuzhu[z+1],shuzhu[z*2+1])

cout<<endl

z--

for(n=0n<geshu*2+2n++)

cout<<" "<<shuzhu[n]

swap(shuzhu[z],shuzhu[z*2])

swap(shuzhu[z+1],shuzhu[z*2+1])

cout<<endl

z--

for(n=0n<geshu*2+2n++)

cout<<" "<<shuzhu[n]

swap(shuzhu[z],shuzhu[z*2])

swap(shuzhu[z],shuzhu[z*2+1])

cout<<endl

z--

swap(shuzhu[geshu*2-2],shuzhu[z])

swap(shuzhu[geshu*2-1],shuzhu[z+1])

y++

}

}

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