用c语言写一个简易抽奖程式，要求涉及到档案的 *** 作
#include <bits/stdc++.h>using namespace std int n,a[233] int main(){ freopen("a.in","r",stdin) freopen("a.out","w",stdout) scanf("%d",&n) for (int i=0i<ni++) scanf("%d",&a[i]) printf("%d\n",a[rand()%n]) }
求用c语搏举言自制一个简易抽奖程式
用data.txt档案储存以下内容：
13725528132 李桂荣
13725528131 李二来
13725528133 张荣刚
13725528130 荣南
13725528137 王三
13725528138 吴立
13725528139 郭德纲
13725528140 周星驰
13725528141 张曼玉
13725528142 张艺谋
13725528152 秦香莲
13725528162 潘金莲
13725528172 李大嘴
13725528182 展堂
原始码如下
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#define MAX_NUM 9999
定义储存人名和电话的资料结构
struct Person
{
char name[20]
char telno[15]
char award
}
int num = 0统计人数
FILE *fp档案指标
Person persons[MAX_NUM]定义阵列
int awarder_1[1] = {-1}一等奖
int awarder_2[2] = {-1, -1}二等奖
int awarder_3[5] = {-1, -1, -1, -1, -1}三等奖
读取档案
void readdata()
{
int i = 0阵列下标
Person person
档案开启
fp = fopen("data.txt", "r")
if (fp == NULL)
{
printf("开启档案data.txt失败!\n")
return
}
当档案不为空
while (!feof(fp))
{
num ++
fscanf(fp, "%s", person.telno)
fscanf(fp, "%s", person.name)
person.award = 'F'
persons[i++] = person
}
}
初始化标识
void init()
{
for(int i = 0i <numi++)
{
persons[i].award = 'F'
}
}
显示单个中奖资讯
void info( int i)
{
printf("手机旁银谈号码: %s 姓名: %s\n", persons[i].telno, persons[i].name)
}
void main()
{
char again = 'Y'
读取档案
readdata()
printf("简单抽奖程式\n")
srand((long)time(0))
while(again == 'Y' || again == 'y')
{
初始化标识
init()
printf("\n开始抽第一等奖(1名)，按任意键开始...\n")
getchar()
awarder_1[0] = abs(rand() % num)
while (persons[awarder_1[0]].award == 'T')
{
awarder_1[0] = rand() % num
}
persons[awarder_1[0]].award = 'T'
info(awarder_1[0])
printf("\n开始抽第二等奖(2名)\n")
for (int i = 0i <2i++)
{
printf("\n第%d个二等奖,按任意键开始...\n", i+1)
getchar()
awarder_2[i] = rand() % num
while (persons[awarder_2[i]].award == 'T')
{
awarder_2[i] = rand() % num
}
persons[awarder_2[i]].award = 'T'
info(awarder_2[i])
}
printf("\n\n开始抽第三等奖(5名)\n")
for (i = 0i <5i++)
{
printf("\n第%d个三等奖,按任意键开始...\n", i + 1)
getchar()
awarder_3[i] = rand() % num
while (persons[awarder_3[i]].award == 'T')
{
awarder_3[i] = rand() % num
}
persons[awarder_3[i]].award = 'T'
info(awarder_3[i])
}
printf("\n是否重新开始抽奖?(Y or N)...\n")
again = getchar()
}
getchar()
return
}
C语言怎么写一个简易秒表
用到time.h档案
里面有个clock()函式,返回一个clock_t型别的数字,表示从程式执行开始,CPU的"滴答"数
而在time.h里有个常量CLOCKS_PER_SEC表示每秒钟有多少个"滴答".
这样,(((float)clock())/CLOCKS_PER_SEC)*1000这样的表示式就能得到从程式执行开始到现在的经过的时间.
程式的大致思路是这样的,程式按下1的时候记下当时的程式执行时间.
从这时起,每时刻捡取程式执行时间,然后减去先前的值,就可以得到已经计时的时间了.
只要让使用者按下0结束计时就好了
在conio.h档案里,有个函式kbhit()是个非阻塞函式,用来检查键盘缓冲里有没有按键按下,若有,则返回1,若没有,则返回0,以此来作为判断,若返回1,则捡取按键,测试它是不是0或者1,若返回0,则表示使用者没有动作,继续原来的工作,即继续计时或等待命令.
时间紧，求帮写一个简单C语言程式
#include <stdio.h>
void show(int i)
{
switch(i) {
case 0:
printf("零")
break
case 1:
printf("壹")
break
case 2:
printf("贰")
break
case 3:
printf("叁")
break
case 4:
printf("肆")
break
case 5:
printf("伍")
break
case 6:
printf("陆")
break
case 7:
printf("柒")
break
case 8:
printf("捌")
break
case 9:
printf("玖")
break
}
}
void showwei(int i)
{
if (i != 5 &&i != 9) { 不是万位和亿位
i = i % 4
}
switch(i){
case 2:
printf("拾")
break
case 3:
printf("佰")
break
case 4:
printf("千")
break
case 5:
printf("万")
break
case 9:
printf("亿")
break
}
}
void test1(int n)
{
int i = 0
int j
int b[20]
while(1) {
b[i] = n % 10
i++
n = n / 10
if (n == 0) {
break
}
}
for(j = i - 1j >= 0j--) {
show(b[j]) 输出一二三四
}
printf("\n")
for(j = i - 1j >= 0j--) {
show(b[j])
showwei(j +1) 输出十百千万
}
printf("\n")
}
void main()
{
long int i
printf("请输入整数：")
scanf("%ld",&i)
test1(i) 输出繁体
}
用c语言写一个简易数独的思路。要程式码
#include<stdio.h>int num[9][9], xy[9][9]int check(int x, int y) {int i, m, n for(i = 0i <9i++)if ((xy[x][y] == xy[i][y]&&i != x)||(xy[x][y] == xy[x][i]&&i != y))return 0 for(i = 0, m = x / 3 * 3, n = y / 3 * 3i <9i++)if (xy[x][y] == xy[m + i / 3][n + i % 3]&&m + i / 3 != x&&n + i % 3 != y)return 0 return 1}void search(int x, int y) {if (x == 9)for(x = 0x <9x++) {for(y = 0y <9y++)printf("%d ", xy[x][y]) printf("\n") }else if (num[x][y])search(x + (y + 1) / 9, (y + 1) % 9) elsefor(xy[x][y] = 1xy[x][y] <= 9xy[x][y]++)if (check(x, y))search(x + (y + 1) / 9, (y + 1) % 9) return}int main() {int i, j for(i = 0i <9i++)for(j = 0j <9j++) {scanf("%d", &num[i][j]) xy[i][j] = num[i][j] }search(0, 0) return 0} 输入为9行9列整数，已知的整数填写对应的数字，尚待计算的未知数字填写0。
该程式码的思路很简单，就是从第一行第一列开始依次填入数字，检查是否是在同一行、同一列、同一宫有没有填入重复数字，如果没有就继续填入下一个数字，如果有就返回。
虽然效率稍低，但原理简单、表述直白、易于理解，更有效率的程式码是使用十字连结串列完成，如有兴趣可继续深入
编写C语言程式,实现对磁碟档案的 *** 作
#include "stdio.h"
#include "string.h"
main()
{
FILE *fp
fp=fopen("data.txt","w")
char a[100]="hello world!"
fwrite(a,strlen(a)+1 ,sizeof(char),fp )
fclose(fp)
fp=fopen("data.txt","r")
char b[100]
fread(b,strlen(a)+1 ,sizeof(char),fp )
fclose(fp)
printf("%s\n",b)
}
c语言，写一个抽奖程式，可以选择重复抽奖也可以选择退出，能调概率
srand（time（0））；
int chance；
输入概率（10 - 100 %）
rand（） % chance == 0 为中奖；
其他不中；
帮忙写一个c语言程式，作用是写一个分割档案的程式，原档案太大，无法装的下，需要分割
#include <stdio.h>#include <string.h>#define TARGET_SIZE (100*1024*1024) 分割为100M一个档案int main(){char name[100] FILE *in, *out char target[100] int t=1,c, n=0 printf("input source file name and path:") gets(name) in = fopen(name, "rb") if(in == NULL){printf("can not read file\n") return -1 }while(!feof(in)){sprintf(target, "%s.part%d",name, t) out = fopen(target, "wb") if(out == NULL){printf("open %d file to write failed\n",t) return -1 }n = 0 while((c=fgetc(in)) != EOF &&n<TARGET_SIZE){fputc(c, out) n++ }fclose(out) t ++ }fclose(in) printf("done! the file is cut to %d file(s)\n", t-1) return 0}
用data.txt文件保存以下内容：13725528132 李桂荣
13725528131 李二来
13725528133 张荣刚
13725528130 荣南
13725528137 王三
13725528138 吴立
13725528139 郭德纲
13725528140 周星驰
13725528141 张曼玉
13725528142 张艺谋
13725528152 秦香莲
13725528162 潘金莲
13725528172 李大嘴
13725528182 展堂
//源代码如下
#include <stdio.h>
#include <stdlib.h>
#include <time.h>
#define MAX_NUM 9999
//定义保存人名和电话的数据结构
struct Person
{
char name[20]
char telno[15]
char award
}
int num = 0//统计人数
FILE *fp//文件指针
Person persons[MAX_NUM]//定义数组
int awarder_1[1] = {-1}//一等奖
int awarder_2[2] = {-1, -1}/弊让毁/二等奖
int awarder_3[5] = {-1, -1, -1, -1, -1}//三等奖
//读取文件
void readdata()
{
int i = 0//数组下标
Person person
//文件打开
fp = fopen("data.txt", "r")
if (fp == NULL)
{
printf("打开文件data.txt失败!\n")
return
}
//当文件不为空
while (!feof(fp))
{
num ++
fscanf(fp, "%s", person.telno)
fscanf(fp, "%s", person.name)
person.award = 'F'
persons[i++] = person
}
}
//初始化标识
void init()
{
for(int i = 0i <numi++)
{
persons[i].award = 'F'
}
}
//显示单个中奖信息
void info( int i)
{
printf("手机号码: %s 姓名: %s\n", persons[i].telno, persons[i].name)
}
void main()
{
char again = 'Y'
//读取文件
readdata()
printf("简单抽奖程序\n")
srand((long)time(0))
while(again == 'Y' || again == 'y')
{
//初始化标识
init()
printf("\n开始抽第一等奖(1名)，按任意键开始...\n")
getchar()
awarder_1[0] = abs(rand() % num)
while (persons[awarder_1[0]].award == 'T')
{
awarder_1[0] = rand() % num
}
persons[awarder_1[0]].award = 'T'
info(awarder_1[0])
printf("\n开始抽第二等奖(2名)\n")
for (int i = 0i <2i++)
{
printf("\n第%d个二等奖,按任意键开始...\n", i+1)
getchar()
awarder_2[i] = rand() % num
while (persons[awarder_2[i]].award == 'T'滑缓)
{
awarder_2[i] = rand() % num
}
persons[awarder_2[i]].award = 'T'
info(awarder_2[i])
}
printf("\n\n开始抽第三租备等奖(5名)\n")
for (i = 0i <5i++)
{
printf("\n第%d个三等奖,按任意键开始...\n", i + 1)
getchar()
awarder_3[i] = rand() % num
while (persons[awarder_3[i]].award == 'T')
{
awarder_3[i] = rand() % num
}
persons[awarder_3[i]].award = 'T'
info(awarder_3[i])
}
printf("\n是否重新开始抽奖?(Y or N)...\n")
again = getchar()
}
getchar()
return
}
#include<stdio.h>#include <conio.h>
#include <stdlib.h>
#include <memory.h>
#include <string.h>
#include <time.h>
#define AWARDER_NUM 10
typedef struct tag_award
{
char ID[20]
char name[20]
char telNo[20]
char address[50]
}AWARDER
AWARDER * awarder = new AWARDER[AWARDER_NUM]
int first_award[1] = {-1}
int second_award[2] = {-1,-1}
int third_award[5] ={-1,-1,-1,-1,-1}
int awarder_num = 0
void info_login()
{
if(awarder_num >= AWARDER_NUM)
{
AWARDER * new_awarder = new AWARDER[awarder_num + AWARDER_NUM]
memcpy(new_awarder,awarder,awarder_num*sizeof(AWARDER))
delete awarder
awarder = new_awarder
}
printf("身份z号："罩亩)
scanf("%s",awarder[awarder_num].ID)
printf("姓名：")
scanf("%s",awarder[awarder_num].name)
printf("电话号码：")
scanf("%s",awarder[awarder_num].telNo)
printf("家庭住址：")
scanf("%s",awarder[awarder_num].address)
awarder_num++
}
void info_delete()
{
char name[20]
printf("输入您要删除的抽奖者的姓名：")
scanf("%s",name)
for(int i=0i<awarder_numi++)
{
if (strcmp(awarder[i].name,name) == 0)
{
printf("您选择删除的颂闷氏抽奖者的信息如下：\n")
printf("身份z号：%s\n",awarder[i].ID)
printf("姓名：%s\n",awarder[i].name)
printf("电话号码：%s\n",awarder[i].telNo)
printf("家庭住址：%s\n",awarder[i].address)
break
}
}
if(i == awarder_num)
{
printf("没有找到您输入的抽奖者！\n")
}
else
{
char c
printf("您确定要删除吗？(Y//N)")
fflush(stdin)
scanf("%c",&c)
if(c == 'Y' || c == 'y')
{
AWARDER * new_award = new AWARDER[awarder_num-1]
if(i <= 0)
memcpy(new_award,awarder+1,sizeof(AWARDER) * (awarder_num - 1))
else if( i >= awarder_num -1)
memcpy(new_award,awarder,sizeof(AWARDER) * (awarder_num - 1))
else
{
memcpy(new_award,awarder,sizeof(AWARDER) * i)
memcpy(new_award+i,awarder+i+1,sizeof(AWARDER) * (awarder_num - i - 1))
}
awarder_num--
delete awarder
awarder = new_award
}
}
}
void info_modify()
{
char name[20]
printf("输入您要修改的抽奖者的野散姓名：")
scanf("%s",name)
for(int i=0i<awarder_numi++)
{
if (strcmp(awarder[i].name,name) == 0)
{
printf("您选择的抽奖者的信息如下：\n")
printf("身份z号：%s\n",awarder[i].ID)
printf("姓名：%s\n",awarder[i].name)
printf("电话号码：%s\n",awarder[i].telNo)
printf("家庭住址：%s\n",awarder[i].address)
break
}
}
if(i == awarder_num)
{
printf("没有找到您输入的抽奖者！\n")
}
else
{
printf("请输入该抽奖者的新信息：\n")
printf("身份z号：")
scanf("%s",awarder[i].ID)
printf("姓名：")
scanf("%s",awarder[i].name)
printf("电话号码：")
scanf("%s",awarder[i].telNo)
printf("家庭住址：")
scanf("%s",awarder[i].address)
}
}
bool check_over(int cur_award,int awarderNo)
{
if(awarderNo == 1)
{
if(cur_award == first_award[0])
return true
}
else if(awarderNo <= 3)
{
if(cur_award == first_award[0])
return true
for(int i=0i<awarderNo-1i++)
if(cur_award == second_award[i])
return true
}
else if(awarderNo <= 8)
{
if(cur_award == first_award[0])
return true
for(int i=0i<2i++)
if(cur_award == second_award[i])
return true
for(i=0i<awarderNo-3i++)
if(cur_award == third_award[i])
return true
}
return false
}
void award()
{
if(awarder_num <8)
{
printf("人数太少，请添加足够的人再抽奖！\n")
return
}
srand((long)time(0))
char hit_id[20]
printf("\n开始抽第一等奖（1名），按任意键开始...\n")
getch()
while(!kbhit())
{
first_award[0] = rand() % awarder_num
memcpy(hit_id,awarder[first_award[0]].ID,18)
printf("\r")
printf("\r %s",hit_id)
}
printf("\n\n开始抽第二等奖（2名）")
for (int i=0i<2i++)
{
printf("\n第%d个二等奖,按任意键开始...\n",i+1)
getch()
while(!kbhit())
{
second_award[i] = rand() % awarder_num
while(check_over(second_award[i],1+i))
second_award[i] = rand() % awarder_num
memcpy(hit_id,awarder[second_award[i]].ID,18)
printf("\r")
printf("\r %s",hit_id)
}
}
printf("\n\n开始抽第三等奖（5名）")
for (i=0i<5i++)
{
printf("\n第%d个三等奖,按任意键开始...\n",i+1)
getch()
while(!kbhit())
{
third_award[i] = rand() % awarder_num
while(check_over(third_award[i],3+i))
third_award[i] = rand() % awarder_num
memcpy(hit_id,awarder[third_award[i]].ID,20)
printf("\r")
printf("\r %s",hit_id)
}
}
}
void info_show()
{
printf("一等奖获得者：\n")
printf("\t身份z号：%s\n",awarder[first_award[0]].ID)
printf("\t姓名：%s\n",awarder[first_award[0]].name)
printf("\t电话号码：%s\n",awarder[first_award[0]].telNo)
printf("\t家庭住址：%s\n",awarder[first_award[0]].address)
printf("二等奖获得者：\n")
for (int i=0i<2i++)
{
printf("第%d个二等奖获得者：\n")
printf("\t身份z号：%s\n",awarder[second_award[i]].ID)
printf("\t姓名：%s\n",awarder[second_award[i]].name)
printf("\t电话号码：%s\n",awarder[second_award[i]].telNo)
printf("\t家庭住址：%s\n",awarder[second_award[i]].address)
}
printf("三等奖获得者：\n")
for (int i=0i<5i++)
{
printf("第%d个三等奖获得者：\n")
printf("\t身份z号：%s\n",awarder[third_award[i]].ID)
printf("\t姓名：%s\n",awarder[third_award[i]].name)
printf("\t电话号码：%s\n",awarder[third_award[i]].telNo)
printf("\t家庭住址：%s\n",awarder[third_award[i]].address)
}
}
/*提示信息*/
bool raise()
{
printf("\n请输入你需要的 *** 作代号：\n")
printf("\t1.录入：完成抽奖者信息的输入\n")
printf("\t2.删除：完成抽奖者信息的删除\n")
printf("\t3.修改：允许对已经录入的数据重新进行编辑、修改\n")
printf("\t4.抽奖：开始抽奖！\n")
printf("\t5.显示：显示所有中奖者的信息\n")
printf("\t6.退出。\n")
printf("==>")
int operate
fflush(stdin)
scanf("%d",&operate)
switch(operate)
{
case 1:
info_login()
break
case 2:
info_delete()
break
case 3:
info_modify()
break
case 4:
award()
break
case 5:
info_show()
break
case 6:
return false
default:
break
}
printf("\n *** 作完成。\n")
return true
}
void main()
{
while(raise())
}
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